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yaroslaw [1]
3 years ago
9

Match the following words.

Chemistry
1 answer:
azamat3 years ago
7 0

Answer:

1. active site

2. substrate.

3. activity

4. cofactor

5. complex

6. coenzyme.

Explanation:

1. A substrate binds to an enzyme at the active site where the reaction occurs.

2. In a catalyzed reaction, a reactant is often called a  substrate.

3  activity is a measure of how fast an enzyme can convert the reagent to the  product.

4. An inorganic substance necessary for the function of some enzymes is called a cofactor.

5. When properly aligned, the enzyme and substrate form an enzyme-substrate (ES) complex.

6. A small organic molecule necessary for the function of some enzymes is  called a  coenzyme.

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Explanation:

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2 years ago
Forrest spills some acid on the lab floor. He notifies his teacher and begins to look for baking soda to neutralize the acid on
riadik2000 [5.3K]

The other students in the lab should be notified next in this type of scenario.

<h3>What is an acid?</h3>

This is a substance which donates protons and is very corrosive. It also turns blue litmus paper red.

When it was spilled and baking soda was used to neutralize it on the floor , it is best to inform the other students too so as to prevent them from being exposed by mistake thereby reducing risk of injury.

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5 0
1 year ago
Why do atoms tend to be bonded to other atoms?
Aleks04 [339]

Answer:

Atoms are often more stable when bonded to other atoms

Explanation:

Like for example let's say ionic bonds..... Since one atom has to lose specific electrons to be stable and the other needs the electrons from the other atom to be stable.....

3 0
3 years ago
Read 2 more answers
63Ni decays by a first-order process via the emission of a beta particle. The 63Ni isotope has a half-life of 100. years. How lo
rewona [7]

Answer:

151.4863 years

Explanation:

Half life, t1/2 = 100 years

Initial concentration,[A]o = 100%

Final concentration, [A] = 35% (after 65% have been decayed)

Time = ?

Half life for a first Order reaction is given as;

t1/2 = ln (2) / k

k = ln(2) / 100

k = 0.00693y-1

The integral rate law for first order reactions is given as;

ln[A] = ln[A]o − kt

kt = ln[A]o - ln[A]

t = ( ln[A]o - ln[A]) / k

t = [ln(100) - ln(35)] /0.00693

t = 1.0498 / 0.00693

t = 151.4863 years

8 0
3 years ago
In a titration of a solution of unknown concentration of calcium hydroxide against hydrochloric acid (concentration 0.9mol/dm3),
bearhunter [10]
Hi dear
I hope that will be helpful

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2 years ago
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