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2 years ago

If f(x)=3|x-2|, what is f(5.9)? a: 9 b: 10 c: 11 d: 12

2 answers:

7 0

$|a|= \left\{\begin{array}{ccc}a&if&a\geq0\\-a&if&a \ \textless \ 0\end{array}\right\\\\f(x)=3|x-2|\\\\f(5.9)=3|5.9-2|=3|3.9|=3\cdot3.9=11.7$

aliina [53]2 years ago

3 0

Answer:

The answer is C.11

Step-by-step explanation:

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tigry1 [53]

Step-by-step explanation:

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8 0

2 years ago

352, 345, 338, ...<br> Find the 43rd term.

Artemon [7]

Answer:

Step-by-step explanation:

first term = a = 352

Common difference = d = second term - first term

= 345 - 352

= (-7)

nth term = a + (n-1)*d

43rd term = 352 + (43-1)*(-7)

= 352 + 42 *(-7)

= 352 - 294

= 58

3 0

2 years ago

Find the measure of the the sides of DEF then classify it by it sides. <br> D(8,-6) E(-1,-3) F(-2,5)

Mama L [17]

Answer:

Part a) The measure of the sides of triangle DEF are

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Part b) Is a scalene triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

$d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}$

$d=\sqrt{(3)^{2}+(9)^{2}}$

$d_D_E=\sqrt{90}\ units$

step 2

Find the length side EF

E(-1,-3) F(-2,5)

substitute in the formula

$d=\sqrt{(5+3)^{2}+(-2+1)^{2}}$

$d=\sqrt{(8)^{2}+(-1)^{2}}$

$d_E_F=\sqrt{65}\ units$

step 3

Find the length side DF

D(8,-6) F(-2,5)

substitute in the formula

$d=\sqrt{(5+6)^{2}+(-2-8)^{2}}$

$d=\sqrt{(11)^{2}+(-10)^{2}}$

$d_D_F=\sqrt{221}\ units$

step 4

Classify the triangle by the measure of its sides

we have

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

6 0

3 years ago

8 hr= how many min???<br> Please help fast!

aleksklad [387]

The answer is 8h=480min

6 0

2 years ago

Read 2 more answers

David and Josh are both practicing for an upcoming swim tournament. Every week, David swims for 3x hours at an average speed of

Ugo [173]

3x = 5(x-4)

I am not sure about the equal sign though.

5 0

3 years ago

Read 2 more answers