we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Lets say two numbers are x and y
x+y=70-----------------------eq1
x=4y--------------------eq2
4y+y=70
5y=70
y=70/5
y=14
then x=4*14
x=56
Answer:
1,462.50
Step-by-step explanation:
6500
x.045
=292.50 per year
x. 5 years
=1,462.50
Y= -2.5
the midline is basically the line where the distance is the same to the line from the max and the min
