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almond37 [142]
3 years ago
15

1.5 tons. To make the car faster, you replaced the steel body with carbon-fiber and reduced the weight by 300 pounds. How much d

oes your race car weigh now?
Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

1 ton = 2,000 pounds
1.5 tons = 3,000 pounds

After reducing the weight by 300 pounds,
the car now weighs

               (3,000 pounds)  -  (300 pounds)  =  2,700 pounds .

                                   (that's  2,700/2,000 =  1.35 tons)
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Alenkasestr [34]

PART A)

The rate of change is -40 songs each week, because the amount of songs left to be downloaded decrease by 40 every week.

<span>the initial value is 200 at 0 weeks, which means that there are 200 songs to be downloaded at the beginning</span>

PART B)

<span><span><span> <span><span>calculate the slope:
</span><span> m = (y2- y1)/(x2 - x1) = (160 - 200)/(1 - 0)
m = -40
now use the line equation in form of point-slope
y - y1 = m(x - x1)
y - 200 = -40(x - 0)
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5 0
4 years ago
Help please!!
denpristay [2]

Answer:

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8 0
3 years ago
The length of a rectangle is 7 ft longer than twice the width. If the perimeter is 92 ft find the length and width of the rectan
user100 [1]

Width of the rectangle is 13 ft and length of the rectangle is 33 ft

<u>Step-by-step explanation:</u>

Step 1:

Given perimeter of the rectangle = 92 ft. Let the width be x, then the length of the rectangle = 2x + 7. Use the formula for perimeter of a rectangle = 2(length + width) to find the dimensions.

92 = 2(2x + 7 + x) = 2(3x + 7) = 6x + 14

⇒ 92 = 6x + 14

⇒ 78 = 6x

⇒ x = 78/6

∴ x = 13 ft

⇒ Width of the rectangle = 13 ft

∴ Length of the rectangle = 2x + 7 = 26 + 7 = 33 ft

4 0
3 years ago
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zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
3 years ago
Can y’all help me on question 11?!
Shtirlitz [24]

Answer:

a

Step-by-step explanation:

if there are zero two's, then it is zero

6 0
3 years ago
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