All categories

3 years ago

What is 14.7 x 11.361

Mathematics

2 answers:

S_A_V [24]3 years ago

8 0

167.0067 that is the right answer

Y_Kistochka [10]3 years ago

4 0

167.0067
I hope this helps!

You might be interested in

What happens when you add and subtract integers

Furkat [3]

When u add it stays the same but for subtraction u change the sign.

Example: 2- (-5)=7

5 0

3 years ago

Read 2 more answers

Which number should follow in this series: 64/64 9/12 6/12

zheka24 [161]

Answer: $\frac{1}{4}$

Step-by-step explanation:

You can reduce the fractions, then:

$\frac{64}{64}=1$

$\frac{9}{12}=\frac{3}{4}$

$\frac{6}{12}=\frac{3}{6}=\frac{1}{2}$

Rewrite them as following:

$1,\frac{3}{4},\frac{1}{2}$

If you subtract the first number and the second number, you obtain:

$1-\frac{3}{4}=\frac{1}{4}$

If you subtract the second number and the second number, you obtain:

$\frac{3}{4}-\frac{1}{2}=\frac{1}{4}$

Therefore, you must subtract $\frac{1}{2}$ and $\frac{1}{4}$ to obtain the number asked. Then, this is:

$\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

6 0

3 years ago

Read 2 more answers

HAPPY B DAY TOO meeeeeee

stich3 [128]

Answer:

happy birthday may god bless you

3 0

2 years ago

Read 2 more answers

Is side “a” considered a leg or the hypotenuse in this right triangle?

skelet666 [1.2K]

Answer:

A leg.

Step-by-step explanation:

The hypotenuse is always the side that is across from the corner. In this triangle, the hypotenuse is 14.

6 0

3 years ago

Read 2 more answers

(10.02)

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

3 years ago