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Mekhanik [1.2K]
3 years ago
12

HELP ASAP PLZ :)

Mathematics
1 answer:
Natalija [7]3 years ago
3 0

for the triangle...

b=2h

a=(1\2).bh=648

(1/2).2h.h=648

h2=648

h-18|2 in

h=36|2 in

for the rectangle...

L=3+w

a=l+w=648

{3+w}w=648

w2+3w-648=0

Only positive W values make sense here..

w-24=0

w=24 in

So..

L=3+24

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Holly made 12 pair of earrings for each of her girlfriends. To wrap the pairs individually, she creates a simple cardboard gift
Mekhanik [1.2K]

Answer:

3280cm²

Step-by-step explanation:

We are told the gift box is folded into a Pyramid with a square base.

Hence, we are to find the Surface Area of a square pyramid

From the question, we are given:

Length of the base of the square = 10cm

Triangle

Side length = 10cm

Height = 8 2/3 cm

A square Pyramid has 5 faces: 4 triangles and 1 square.

Step 1

Find the Area of the square

Formula = Side length² this is because all the side of a square is equal.

Length of the base = 10cm

Area of the square = (10cm)²

= 100cm²

Step 2

Find the Area of the triangle. We are told the 4 triangles are equilateral, which means their side are equal.

Hence, for one triangle.

Area of a triangle = 1/2 × base × height

Base = side length = 10cm

Height = 8 2/3 = 8.6666666667cm

Area of a triangle = 1/2 × 10 × 8.6666666667

Area of a triangle = 43.333333333cm²

Since we have 4 triangles

We would have : 4 × 43.333333333cm²

= 173.33333333cm²

The Area of the 4 equilateral triangles =

173.33333333cm²

Step 3

The Surface area of the Square Pyramid

= Sum of the areas of all the faces.

= 100cm² + 173.33333333cm²

= 273.33333333cm²

Therefore, the minimum amount of cardboard needed to make one gift box = 273.33333333cm²

Step 4

The minimum amount of cardboard Holly needs to create 12 gift boxes to wrap each pair of earrings individually is calculated as: 12 × 273.33333333cm²

= 3280cm²

7 0
3 years ago
Find 62.7% of 177. Round to the nearest thousandth.
PilotLPTM [1.2K]

Answer:

110.979

Step-by-step explanation:

62.7% * 177 = 0.627 * 177 = 110.979

8 0
2 years ago
Directions: Complete all 3 questions. Make sure you include a graph, work and conclusion.
Simora [160]

Prove that the quadrilateral whose vertices are I(-2,3), J(2,6), K(7,6), and L(3, 3) is a rhombus.

I think in these problems the first step is to express each side as a vector.  A vector is the difference between points.  When two sides have the same vector (or negatives) it means they're parallel and congruent.  So in a rhombus IJKL the vectors IJ and LK should be the same, as should JK and IL.  That much assures a parallelogram; we check IJ and JK are congruent to complete the crowing of the rhombus.

Let's calculate these vectors:

IJ = J - I = (2,6) - (-2,3) = (2 - -2, 6 - 3) = (4, 3)

LK = K - L = (7, 6) - (3, 3) = (4, 3)

IJ = LK, so far so good

(Note: If you haven't got to vectors yet you can just show the two sides are the same length, 5, and have the same slope, 3/4, both of which can be read off the vectors.)

JK = K - J = (7,6) - (2,6) = (5,0)

IL = L - I = (3, 3) - (-2, 3)  = (5, 0)

Those are the same too.    

Now we have to show IJ ≅ JK

The length of IJ is the cliche √4²+3² = 5, the same as JK, so IJ ≅ JK

We showed all four sides are congruent and we have two pair of parallel sides, so we have a rhombus.

8 0
3 years ago
PLZ HELP ME
iVinArrow [24]

Answer:

y=-1x+8

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

7 0
2 years ago
Find m<LMN if m<LMT=23 degree and m<TMN=144 degree​
rodikova [14]

Answer:

∠LMN = 167°

Step-by-step explanation:

∠LMT = 23°

∠TMN = 144°

∠LMN = ∠LMT + ∠TMN

∠LMN = 23° + 144°

∠LMN = 167°

5 0
2 years ago
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