In a large corporate computer network, user log-ons to the system can be modeled as a Poisson RV with a mean of 25 log-ons per h
our. (20pts) (a) What is the probability that there are no logons in an interval of 6 minutes? (b) What is the probability that the distance between two log-ons be more than one hour?
- Let X be an exponential RV denoting time t in hours from start of interval to until first log-on that arises from Poisson process with the rate λ = 25 log-ons/hr. Its cumulative density function is given by:
F(t) = 1 - e ^ ( - 25*t ) t > 0
A) In this case we are interested in the probability that it takes t = 6/60 = 0.1 hrs until the first log-on. F ( t < 0.1 hr ), we have:
I'm pretty sure the answer is 452.16. The formula is pi times the radius squared times the height. 3.14 times 6 squared time 4. 3.14 times 36 times 4. 113.04 times 4. 452.16.