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UkoKoshka [18]
3 years ago
15

How does weathering, erosion and deposition shape the Earth and contribute to the rock cycle? Weathering, erosion and deposition

shape the Earth by ______ and contribute to the rock cycle by ______.
Physics
1 answer:
Andrei [34K]3 years ago
7 0

Answer:

Weathering, erosion and deposition over millions of years can destroy and break apart rocks which in turn can cause sediments which is directly involved in the rock cycle.

Explanation:

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Prompt how does melanin provide protection against skin cancer?
Wittaler [7]

Answer:

absorb , it absorbs it ...

4 0
3 years ago
Monochromatic light is incident on a pair of slits that are separated by 0.240 mm. The screen is 2.80 m away from the slits. (As
Makovka662 [10]

Answer:

λ = 1.388 x 10⁻⁶ m = 1388 nm

Explanation:

We can use the Young's Double Slit experiment formula here to solve this numerical:

\Delta x = \frac{\lambda L}{d} \\\\\lambda = \frac{\Delta x d}{L}\\

where,

λ = wavelength = ?

Δx = distance between adjacent bright fringes = 1.62 cm = 0.0162 m

d = slit separation = 0.24 mm = 0.00024 m

L = distance from screen to slits = 2.8 m

Therefore,

\lambda = \frac{(0.0162\ m)(0.00024\ m)}{2.8\ m} \\

<u>λ = 1.388 x 10⁻⁶ m = 1388 nm</u>

6 0
3 years ago
What is the highest degrees above the horizon the moon ever gets during the year in the Yakima Valley ?
Ivahew [28]

The trickiest part of this problem was making sure where the Yakima Valley is.
OK so it's generally around the city of the same name in Washington State.

Just for a place to work with, I picked the Yakima Valley Junior College, at the
corner of W Nob Hill Blvd and S16th Ave in Yakima.  The latitude in the middle
of that intersection is 46.585° North.  <u>That's</u> the number we need.

Here's how I would do it:

-- The altitude of the due-south point on the celestial equator is always
(90° - latitude), no matter what the date or time of day.

-- The highest above the celestial equator that the ecliptic ever gets
is about 23.5°. 

-- The mean inclination of the moon's orbit to the ecliptic is 5.14°, so
that's the highest above the ecliptic that the moon can ever appear
in the sky.

This sets the limit of the highest in the sky that the moon can ever appear.

90° - 46.585° + 23.5° + 5.14° = 72.1° above the horizon .

That doesn't happen regularly.  It would depend on everything coming
together at the same time ... the moon happens to be at the point in its
orbit that's 5.14° above ==> (the point on the ecliptic that's 23.5° above
the celestial equator).

Depending on the time of year, that can be any time of the day or night.

The most striking combination is at midnight, within a day or two of the
Winter solstice, when the moon happens to be full.

In general, the Full Moon closest to the Winter solstice is going to be
the moon highest in the sky.  Then it's going to be somewhere near
67° above the horizon at midnight.


5 0
3 years ago
A ball is projected into the air with 100 j of kinetic energy which is transformed to gravitational potential energy at the top
raketka [301]
<span>when it returns to its original level after encountering air resistance, its kinetic energy is decreased. 
In fact, part of the energy has been dissipated due to the air resistance.

The mechanical energy of the ball as it starts the motion is:
</span>E=K = 100 J
<span>where K is the kinetic energy, and where there is no potential energy since we use the initial height of the ball as reference level.
If there is no air resistance, this total energy is conserved, therefore when the ball returns to its original height, the kinetic energy will still be 100 J. However, because of the presence of the air resistance, the total mechanical energy is not conserved, and part of the total energy of the ball has been dissipated through the air. Therefore, when the ball returns to its original level, the kinetic energy will be less than 100 J.</span>
3 0
4 years ago
Technician A says that all injectors in a sequential fuel injection system often use the same power wire. Technician B says that
marusya05 [52]

Answer:

The answer is Technician B

8 0
3 years ago
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