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2 years ago

I really need help with this, so please respond as soon a possible

Mathematics

2 answers:

nexus9112 [7]2 years ago

8 0

Answer:

2x-3

Step-by-step explanation:

Rise over Run 2/1 =2x and the y Intercept is -3

marishachu [46]2 years ago

3 0

Answer:

Step-by-step explanation:

The graph is a straight line graph. The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

From the graph,

y2 = - 5

y1 = 1

x 2 = 1

x1 = -2

Slope = (- 5 -1)/(1 - -2) = -6/3 = -2

m = -2

The equation becomes

y = -2x + c

We need to determine c. Let us use (1,-5)

-5 = -2 ×1 + c

-5 = -2 + c

c = -5 + 2 = -3

The equation is

y = -2x -3

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Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

nataly862011 [7]

Let (x, y, z) be a point on the plane in the first octant. The box formed by this point has volume xyz, and you want to maximize this subject to the equation of the plane.

Use the method of Lagrange multipliers: the Lagrangian is

L(x, y, z) = xyz - λ (x + 2y + 3z - 6)

Find its critical points:

∂L/∂x = yz - λ = 0

∂L/∂y = xz - 2λ = 0

∂L/∂z = xy - 3λ = 0

∂L/∂λ = -(x + 2y + 3z - 6) = 0

Solving the first three equations for λ gives

λ = yz = xz/2 = xy/3

Solve these equations for y and z :

• yz = xz/2 => y = x/2 => 2y = x

• yz = xy/3 => z = x/3 => 3z = x

Substitute these solutions into the last equation and solve for x, then again for y and z :

x + 2y + 3z - 6 = 3x - 6 = 0 => 3x = 6 => x = 2, y = 1, z = 2/3

At this critical point, the maximum volume is

xyz = 2*1*2/3 = 4/3

4 0

3 years ago

Idently the graph of f(x) = 3(x - 1) - 4. Then identity the vertex and ads of symmetry find the minimum value of and describe wh

Vesna [10]

Answer:

See below

Step-by-step explanation:

I assume you mean $f(x) = 3(x-1)^2-4$

The equation is already in vertex form $f(x)=a(x-h)^2+k$ where $a$ affects how "fat" or "skinny" the parabola is and $(h,k)$ is the vertex. Therefore, the vertex is $(h,k)\rightarrow(1,-4)$ .

The axis of symmetry is a line where the parabola is cut into two congruent halves. This is defined as $x=h$ for a parabola with a vertical axis. Hence, the axis of symmetry is $x=1$ .

The minimum value is the smallest value in the range of the function. In the case of a parabola, the y-coordinate of the vertex is the minimum value. Therefore, the minimum value is $y=-4$ .

The interval where the function is decreasing is $(-\infty,1)$

The interval where the function is increasing is $(1,\infty)$

8 0

2 years ago

Which equation shows y=−12x+4 is in standard form? 2x + y = 8 2x−y=8 x + 2y = 8 x+2y=−8

drek231 [11]

Answer:

Step-by-step explanation:

The standard form of an equation of a line:

$Ax+By=C$

We have:

$y=-\dfrac{1}{2}x+4$

Convert:

$y=-\dfrac{1}{2}x+4$ multiply both sides by 2

$2y=-x+8$ add x to both sides

$x+2y=8$

3 0

3 years ago

Write each number in standard form: (3 x 100,000) + (4 x 1000) + (2 x 10)

Zepler [3.9K]

$3\times100000 = 3\times10^6 \\ 4\times1000 = 4\times10^3 \\ 2\times10 = 2\times10^1$

So the final statement would be:
$(3\times10^6) + (4\times10^3) + (2\times10^1)$

6 0

3 years ago

How do you find range

Tamiku [17]

First order the data from least to greatest, then subtract the smallest value from the largest value in the set.

5 0

3 years ago

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I really need help with this, so please respond as soon a possible​

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