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luda_lava [24]
3 years ago
12

Plz help ASAP really need it

Mathematics
2 answers:
Keith_Richards [23]3 years ago
8 0

fjkenfnrfgjvhdfbvourgfn eiurfkjeffujkkf, sufjksfdsf

Kruka [31]3 years ago
3 0

Answer: Both of the ones on the right side of the answers

Hope this helped :)

Please mark me as Brainliest

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12×6=(8×6)+(_×6)=answer this question
zubka84 [21]
4.

12 - 8 = 4

Hope this helps!
8 0
3 years ago
Brookton Brothers Supermarket sells 12 apples for $3.00. Kramer's Supermarket sells 18 apples for $4.00. Which store has the bet
otez555 [7]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
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Suppose Becky invests in an annuity that pays 4.3% annual interest, compounded monthly and contributes $225 every month for 20 y
aleksklad [387]

Answer:

$85365.90

Step-by-step explanation:

Let's start by finding the effective rate of interest

.043/12=.00385333

225*\frac{(1+.00385333)^{20*12}-1}{.00385333}=85365.89513

4 0
3 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
HACTEHA [7]

Answer:

(a) The value of P (X ≤ 2) is 0.8729.

(b) The value of P (X ≥ 5) is 0.0072.

(c) The value of P (1 ≤ X ≤ 4) is 0.7154.

(d) The probability that none of the 25 boards is defective is 0.2774.

(e) The expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defective boards.

The probability that a circuit board is defective is, <em>p</em> = 0.05.

The sample of boards selected is of size, <em>n</em> = 25.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={25\choose x}0.05^{x}(1-0.05)^{25-x};\ x=0,1,2,3...

(a)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

P(X\leq =x)=\sum\limits^{2}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.2774+0.3650+0.2305\\=0.8729

Thus, the value of P (X ≤ 2) is 0.8729.

(b)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = 1 - P (X < 5)

              =1-\sum\limits^{4}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=1-0.9928\\=0.0072

Thus, the value of P (X ≥ 5) is 0.0072.

(c)

Compute the value of P (1 ≤ X ≤ 4) as follows:

P (1 ≤ X ≤ 4) = P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

                   =\sum\limits^{4}_{x=1}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.3650+0.2305+0.0930+0.0269\\=0.7154

Thus, the value of P (1 ≤ X ≤ 4) is 0.7154.

(d)

Compute the value of P (X = 0) as follows:

P(X=0)={25\choose 0}0.05^{0}(1-0.05)^{25-0}=1\times 1\times 0.277389=0.2774

Thus, the probability that none of the 25 boards is defective is 0.2774.

(e)

Compute the expected value of <em>X</em> as follows:

E(X)=np=25\times 0.05=1.25

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{25\times 0.05\times (1-0.05)}=1.09

Thus, the expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

8 0
4 years ago
What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction?
dlinn [17]

Step-by-step explanation:

{x}^{2}  =  \frac{9}{16}  \\ first \: step :  \: take \: square \: root \: of \: both \\ sides. \\  \sqrt{ {x}^{2} }  =  \pm  \sqrt{\frac{9}{16} }  \\ x =  \pm \frac{3}{4}  \\

8 0
3 years ago
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