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kakasveta [241]
3 years ago
12

The expression equivalent to (3y+8x)+(4x-8y)

Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

= 12x - 5y

Step-by-step explanation:

Given that:

=(3y+8x)+(4x-8y)

Now simplify by removing brackets:

= 3y + 8x + 4x - 8y

Add the same terms:

= 12x - 5y

i hope it will help you!

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It would go over the five, so im guessing the hundreds

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What is the formula for:
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Answer:

A) (Triangle) So, the area A of a triangle is given by the formula A=12bh where b is the base and h is the height of the triangle. Example: Find the area of the triangle. The area A of a triangle is given by the formula A=12bh where b is the base and h is the height of the triangle.

B) We know that the general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius.

C)The parallelogram area can be calculated, using its base and height.  

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Using Base and Height A = b × h

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Hope this helps!

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7 0
3 years ago
The times for five sprinters in a 50 meter dash were 6.72 seconds 6.4 seconds 6.08 and 7.03 seconds in 6.75 seconds right these
andreev551 [17]

Answer:

Fastest to slowest = 6.08 > 6.4 > 6.72 > 6.75 > 7.03

Step-by-step explanation:

The person who completes the 50-meter race within the shortest possible time is the fastest sprinter. Here, the third sprinter crossed the line in 6.08 seconds, whereas the 4th sprinter crossed the line in 7.03 seconds. That is why the third sprinter has won the race, and he becomes the fastest. On the contrary, the fourth person takes the most time to complete the race, meaning he is the slowest.

6 0
3 years ago
A circle with a diameter of 10 has its center in the first quadrant. The lines y = -3 and x = -1 are tangent to the circle. Writ
yuradex [85]

Answer:

34

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Parameterize the plane that contains the three points (−3,1,−2), (−6,−10,−4) and (15,5,20).
Ipatiy [6.2K]

First find any two vectors in the plane, and take their cross product. The cross product will be perpendicular to both of them.

To find any vectors in the plane, take any two of the given points at a time, and treating them as vectors, subtract them. These vector differences are parallel to the plane we want to find.

(-3, 1, -2) - (-6, -10, -4) = (3, 11, 2)

(-3, 1, -2) - (15, 5, 20) = (-18, -4, -22)

Take the cross product to get the normal vector to the plane:

(3, 11, 2) x (-18, -4, -22) = (-234, 30, 186)

Let (x, y, z) be any point on the plane. The vector

(x, y, z) - (-3, 1, -2) = (x + 3, y - 1, z + 2)

runs parallel to the plane, so it's perpendicular to the plane's normal, which means their dot product is 0. This gives us the Cartesian equation for the plane,

(-234, 30, 186) • (x + 3, y - 1, z + 2) = 0

-234(x + 3) + 30(y - 1) + 186(z + 2) = 0

-234x + 30y + 186 = 360

Every coefficient has a GCD of 6, so the equation is equivalent to

-39x + 5y + 31z = 60

Finally - and this is the easiest step - write this in parametric form. Let x = s and y = t, then

z = (60 + 39s - 5t)/31

So the plane can be parameterized by

P(s, t) = (s, t, (60 + 39s - 5t)/31)

where s and t are any real numbers.

8 0
3 years ago
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