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Simpifly 49/84 ...........
1 answer:
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First, we need to work out the total number of students who were being surveyed.
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let
be the number of pets and 
is the probability of owning the number of pets
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let
Answer:
3/11
Step-by-step explanation:
given that a cell phone company has three different production sites
Site name 1 2 3 Total
Production 60% 30% 10% 100%
Recalled 5% 7% 9%
Prob for recall 0.003 0.021 0.009 0.033
Total probability for recall = 0.033
Prob for recall and came from site 3 = 0.009
So required probability
= If a randomly selected cell phone has been recalled, what is the probability that it came from Site 3
=