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grigory [225]
3 years ago
5

Simplify the expression the root of negative sixteen all over the quantity of three minus three i plus the quantity of one minus

two i..
Mathematics
1 answer:
aliya0001 [1]3 years ago
7 0
The first step is to multiply the fraction by (3 +3i) / (3 +3i) to delete the i terms from the denominator:

\frac{ \sqrt{-16} }{3-3i} . \frac{3+31}{3+3i} +1-2i=  \frac{4i(3+3i)}{9+9} +1-2i= \frac{12i-12}{18} +1-2i=

\frac{12i-12+18-36i}{18} = \frac{6-24i}{18} = \frac{1}{3} - \frac{4}{3} i
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A = l × w. Substitute 72 into A and fill in the rest of the equation.

w = l - 1. Plug l - 1 into w

72 = l × (l - 1). Multiply l by (l - 1)

72 = l^2 - l. Subtract 72 from each side.

0 = l^2 - l - 72. Factor.

0 = (l + 8) (l - 9). Set each term equal to zero.

(l + 8) = 0. Subtract 8 from each side.

l = -8. Length cant be a negative number so let's try the other term.

(l - 9) = 0. Add 9 to each side.

l = 9. The length is 9.

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3 years ago
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