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White raven [17]
3 years ago
8

From least to greatest 2.3, 2 4/5, 2.6

Mathematics
1 answer:
algol [13]3 years ago
7 0
2.3, 2.6, 2 4/5

2 4/5= 2.8
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1) Solve the system by elimination?
lesya692 [45]

Answer:

1) (-6,-9)

times the top equation buy -4 so you cancel out the y

so it be -8x+4y=12 no cancel out the y's

so it be -8x=12 and 5x=6

now combined like terms to get -3x= 36

x = -6 now go plug that back in one of the equations to get y

y = -9

2) (-2,-5)

now on this one you going to substitute y= (2x-1) for y in the otheir eqaution

so it look like 3x-(2x-1)=-1

do your combining of like terms and your division & you get x = -2

now plug x in to y=2x-1 to get y = -5

6 0
3 years ago
Find the median, mean, and range.
RSB [31]

Hey there!

The median is 8.5

The mean is 7

The range is 11

Hope this helps!

God bless ❤️

xXxGolferGirlxXx

5 0
3 years ago
Plz help ...........
bogdanovich [222]

Step-by-step explanation:

Given c = longest of triange = 15m

Given b = short side of triangle = 9m

By pythagoras' Theorem,

{c}^{2}  =  {a}^{2}   +  {b}^{2}  \\  {a}^{2}  +  {b}^{2} =  {c}^{2}   \\  {a}^{2}  +  {(9)}^{2}  =  {(15)}^{2}  \\  {a}^{2}  + 81 = 225 \\  {a}^{2}  = 225 - 81 \\  {a}^{2}  = 144 \\ a =  \sqrt{144}  \\  = 12m

6 0
3 years ago
Help me, please!!!!! CORRECT ANSWER GETS BRAINLIEST!!!!!!
katen-ka-za [31]
Hello,

Here is your answer:

The proper answer to your question is..... 200,000=4x-20

When your doing questions like these make sure you pay attention to the question.

Your answer is 200,000=4x-20

If you need anymore help feel free to ask me!

Hope this helps!

5 0
3 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
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