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2 years ago

Felix bought 3 pounds of patatoes for $2.00.At that rate, what would be the price of 2 pounds of potatoes?

Mathematics

2 answers:

Vsevolod [243]2 years ago

5 0

For one pounds is 0.667
for 2 pounds are 1.33

bekas [8.4K]2 years ago

4 0

2.00/ 3= 0.67
2x 0.67=1.31

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Which expression has a positive quotient?

svp [43]

Answer:

Only 1st option Negative three-fourths divided by Negative two-thirds has positive quotient.

Option A is correct.

Step-by-step explanation:

We will solve to find out Which expression has a positive quotient.

We know the division rule: $\frac{-a}{-b}=\frac{a}{b}$ and $\frac{-a}{b}=\frac{-a}{b}$

We will use these rules

1) Negative three-fourths divided by Negative two-thirds

$=\frac{-\frac{3}{4} }{-\frac{2}{3} }\\=-\frac{3}{4}\times -\frac{3}{2}\\=\frac{9}{8}$

The quotient is positive.

2) Negative StartFraction 1 over 8 EndFraction divided by 3 and one-fifth

$\frac{-\frac{1}{8} }{3\frac{1}{5} }\\=\frac{-\frac{1}{8} }{\frac{16}{5} }\\=-\frac{1}{18} \times \frac{5}{16}\\=-\frac{5}{288}$

The quotient is negative.

3) 2 and StartFraction 2 over 7 EndFraction divided by negative one-fifth

$\frac{2\frac{2}{7} }{-\frac{1}{5} }\\= \frac{\frac{16}{7} }{-\frac{1}{5} }\\=\frac{16}{7} \times -5\\=-\frac{80}{7}$

The quotient is negative.

4) Negative 6 divided by Five-thirds

$\frac{-6}{\frac{5}{3} }\\=-6 \times \frac{3}{5}\\=-\frac{18}{5}$

The quotient is negative.

So, only 1st option Negative three-fourths divided by Negative two-thirds has positive quotient.

Option A is correct.

4 0

3 years ago

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Wren bought a baseball card last year for $2.25. This year the price dropped to $.45. What was the percent of decrease in the pr

const2013 [10]

The price:
- last year: $2.25
- this year: $.45
The decrease: $2.25 - $.45 = $1.80
2.25 : 1.80 = 100 : x
2.25 x = 180
x = 180 : 2.25
x = 80
Answer:
The percent of decrease is A ) 80%

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2 years ago

PLEASE HELP IS POSSIBLE :)

Arisa [49]

Answer: 9 inches

Step-by-step explanation:

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3 years ago

A rectangular swimming pool that is 10 ft wide by 16 ft long is surrounded by a cement sidewalk of uniform width. If the area of

Alchen [17]

We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.

The value of x is <span>5 feet. </span>

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