3+98888888888888888888888888888

the length of a swimming pool is 22 ft. the width is 40 ft. if the volume of the pool is 2,500 ft, which equation would you use

pochemuha

As we know that volume is three dimensional so we will multiply width, length and depth
Now as we have to find the depth of the pool so
Volume= length*width*depth
depth=Volume/(length*width)
d=2500/(40*22)
d= 2500/880
depth=2.841ft

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=91%20%5Cdiv%205.915" id="TexFormula1" title="91 \div 5.915" alt="91 \div 5.915" align="absmidd

Vinil7 [7]

15.38462 is the answer i think

8 0

3 years ago

The Green Goober, a wildly unpopular superhero, mixes 3 liters of yellow paint with 5 liters of blue paint to make 8 liters of s

Degger [83]

Let

y------> the amounts (in liters) of yellow paint

b-----> the amounts (in liters) of blue paint

we know that

$\frac{y}{b}=\frac{3}{5}$

so

$y=\frac{3}{5}b$

therefore

the answer is

$y=\frac{3}{5}b$

5 0

3 years ago

Read 2 more answers

1. The data given below includes data from 42 candies, and 7 of them are red. The company that makes the candy claims that 33%

jeyben [28]

Answer:

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The true proportion of red candies made by the company is different from 33%.

Step-by-step explanation:

The hypothesis to determine whether the claim made by the candy company is correct or not is:

H₀: The true proportion of red candies made by the company is 33%, i.e. p = 0.33.

Hₐ: The true proportion of red candies made by the company is different from 33%, i.e. p ≠ 0.33.

A (1 - α)% confidence interval can be constructed to check this claim.

The decision rule is:

If the confidence interval consists the null value then the null hypothesis will not be rejected. Otherwise it will be rejected.

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

n = 42

X = number of red candies = 7

Compute the sample proportion of candies that are red as follows:

$\hat p=\frac{X}{n}=\frac{7}{42}=0.167$

The critical value of z for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table for the critical value.

Compute the 95% confidence interval for true proportion of red candies as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.167\pm 1.96\times \sqrt{\frac{0.167(1-0.167)}{42}}\\=0.16\pm0.1137\\=(0.0463, 0.2737)\\\approx(0.05, 0.27)$

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The confidence interval does not contains the null value.

Thus, the null hypothesis will be rejected at 5% level of significance.

Conclusion:

The true proportion of red candies made by the company is different from 33%.

7 0

3 years ago

Folosind metoda inducției matematice sa se demonstreze ca pentru orice n€ N* au loc egalitatile:

anastassius [24]

Answer:

I dont understand

Step-by-step explanation:

What is it you need help with?

5 0

3 years ago