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Gelneren [198K]
3 years ago
10

Identify each definition that applies to the compound in red. Check all that apply.

Chemistry
2 answers:
igomit [66]3 years ago
8 0

Answer:

Arrhenius Base and Bronsted-Lowry Base

Explanation:

GarryVolchara [31]3 years ago
8 0

Answer: D.

Bronsted-Lowry base

Explanation:

Took the questions on E2020

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Suppose that coal of density 1.5 g/cm^3 is pure carbon. (It is, in fact, much more complicated, but this is a reasonable first a
NISA [10]

Answer:

q = -6464.9 kJ

Explanation:

We are given that the heat of combustion is  ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.

vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³

m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g

mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol

q =  −394 kJ /mol C x 16.41 mol C = -6464.9 kJ

7 0
3 years ago
Suppose you need of Grade 70 tow chain, which has a diameter of and weighs , to tow a car. How would you calculate the mass of t
BabaBlast [244]

Answer: check explanation

Explanation:

In this question we are to find mass. In order to calculate the Mass, We need the values of two parameters, that is, the values given for the grade tow chain, and the value given for the mass per length.

Assuming the mass per length is 3 Kilogram per metre(kg/m) and the grade 70 tow chain length is 5 metre(m).

Therefore, the formula for calculating mass of the chain is given below;

Mass of the chain= mass per unit length(kg/m) × length ---------------------------------------------------------------------------------------------------------------------(1).

Mass of the chain= 3 kg/m × 5 m.

Mass of the chain= 15 kg.

7 0
4 years ago
Due today please please help!! :
adell [148]

Answer:

3,1,4,2

Explanation: the time is the longest for the liquid that has the biggest viscosity

6 0
3 years ago
Thirty (30.0) milliliters of ethane (C2H6) occupy a container at STP. If the container is heated to 300.0 K and the pressure red
wariber [46]

Answer:

44.6millilitres

Explanation:

Using the general gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

V1 = initial volume (L)

T1 = initial temperature (K)

P2 = final pressure (atm)

V2 = final volume (L)

T2 = final temperature (K)

According to this question;

V1 = 30mL

T1 = 273K (STP)

P1 = 1 atm (STP)

V2 = ?

T2 = 300K

P2 = 75.0 kPa = 75 × 0.00987 = 0.74atm

Using P1V1/T1 = P2V2/T2

1 × 30/273 = 0.74×V2/300

30/273 = 0.74V2/300

Cross multiply

300 × 30 = 273 × 0.74V2

9000 = 202.02V2

V2 = 9000/202.02

V2 = 44.55

V2 = 44.6millilitres.

6 0
3 years ago
Ammonium perchlorate is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas , ch
FinnZ [79.3K]

Answer:

2.9 g of water are produced by 9.6 g of ammonium perchlorate

<em>Note: The question is incomplete. The complete question is given below:</em>

<em>Ammonium perchlorate (NH₄ClO₄) is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas (N₂) , chlorine gas (Cl₂), oxygen gas (O₂), water (H₂O) , and a great deal of energy. What mass of water is produced by the reaction of 9.6 g of ammonium perchlorate? Be sure your answer has the correct number of significant digits.</em>

Explanation:

The reaction of ammonium perchlorate (NH₄ClO₄) to produce nitrogen gas (N₂) , chlorine gas (Cl₂), oxygen gas (O₂), water (H₂O) is shown in the balanced chemical equation given below:

2 NH₄ClO₄ →  N₂ +  Cl₂ + 2 O₂ + 4 H₂O

From the equation, 2 moles of ammonium perchlorate produces 4 moles of water, i.e. mole ratio of NH₄ClO₄ to H₂O = 2 : 4 = 1 : 2

molar mass of ammonium perchlorate, NH₄ClO₄ = (14 + 4 * 1 + 35.5 +16 * 4) = 117.5

molar mass of water,  H₂O = (2 * 1 + 16) = 18.0 g

mass of water produced = moles of ammonium perchlorate * 2 * molar mass of water

moles of perchlorate = mass / molar mass = 9.6/117.5

mass of water produced = 9.6/117.5 * 2 * 18.0 g  = 2.94 g of water

Therefore, 2.9 g of water are produced by 9.6 g of ammonium perchlorate

6 0
3 years ago
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