The question is incomplete. Complete question is attached below.
Solution:
The reaction involved in present electrochemical cell is:
Mg(s) + Zn2+(aq.) ↔ Zn(s) + Mg2+ (aq.)
Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.
Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>
Solution:
The reaction involved in present electrochemical cell is:
Mg(s) + Zn2+(aq.) ↔ Zn(s) + Mg2+ (aq.)
Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.
Thus, 2.5<span> moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.</span>