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Savatey [412]
3 years ago
10

Using the reaction C12H22O11 + 12 O2 ->12CO2 + 11H2O (e). How many grams of carbon dioxide can be produced from 456.7g sucros

e
Chemistry
1 answer:
klio [65]3 years ago
7 0

Answer:

704.6 g CO2

Explanation:

MM sucrose = 342.3 g/mol

MM CO2 = 44.01 g/mol

g CO2 = 456.7 g sucrose x (1 mol sucrose/MM sucrose) x (12 moles CO2/1 mol sucrose) x (MM CO2/1mol CO2) = 704.6 g CO2

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alexdok [17]
1. True 2. False 3.false 4. False 5. True
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Which of the following statements is true of glare control?
galina1969 [7]
The correct option is B. 
Indirect lighting refers to fixtures which direct the light upward to bounce off the wall or ceiling to light a room. This type of lighting is diffusely reflected and create less glare compare to direct lighting. Direct lighting usually direct the light downward, directly on to the surface below to provide illumination.
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I need the measurements to the appropriate amount of significant figures on this pleasee
klio [65]

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Explanation:

3 0
3 years ago
4.Calculate the volume of 40g of Helium (He) at rtp.
Oksana_A [137]

Answer:

2.24dm³

Explanation:

Given parameters:

Mass of He = 40g

Unknown:

Volume of Helium  = ?

Solution:

To solve this problem, we convert the given mass to number of moles.

   Number of moles  = \frac{mass}{molar mass}  

   molar mass of He  = 4g/mol

  Number of moles  = \frac{4}{40}   = 0.1mole

So;

                  1 mole of gas at rtp occupies a volume of 22.4dm³

                0.1 mole of He will occupy a volume of 0.1 x 22.4 = 2.24dm³

4 0
3 years ago
To interconvert the concentration units molality (m) and mass percent, you must also know the density of the solution. A) True B
uranmaximum [27]

Answer:

The correct answer is option false.

Explanation:

Molality of the solution defined as moles of substance present in 1 kilogram of   solvent.

Moles = \frac{Mass of solute}}{\text{molar mass of solute}}

Molality=\frac{Moles}{\text{Mass of solvent(kg)}}

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

(w/w\%)_=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.

Mass of solution = Mass of solute + Mass of solvent

7 0
3 years ago
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