Given:
K = 0.71 = Kp
The reaction of sulphur with oxygen is
S(s) + O2(g) ---> SO2(g)
initial Pressure 6.90 0
Change -x +x
Equilibrium 6.90-x x
Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)
4.899 - 0.71x = x
4.899 = 1.71x
x = 2.86 atm = pressure of SO2 formed
temperature = 950 C = 950 + 273.15 K = 1223.15 K
Volume = 50 L
Let us calculate moles of SO2 formed using ideal gas equation as
PV = nRT
R = gas constant = 0.0821 L atm / mol K
putting other values
n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles
Moles of Sulphur required = 1.42 moles
Mass of sulphur required or consumed = moles X atomic mass of sulphur
mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg of sulphur
Tetraamminedichloridoiron(3) nitrate
Answer:
Answer choice B
Explanation:
Since you do not know the volume of the liquid in each beaker, the one in the smaller beaker could have more substance and therefore more thermal energy. If they had the same amount of substance, then the more voluminous one would radiate faster. However, since you do not know this, there is no way to tell. PM me if you have more questions. Hope this helps!
Answer:
6.1 cm³
Explanation:
To solve this problem we first need to keep in mind <em>Archimedes' principle</em>:
- The volume of water (or any fluid) displaced by a submerged object is equal to the object's volume.
With that in mind we <u>calculate the volume of the granite piece in mililiters</u>:
- Volume displaced = 47.6 mL - 41.5 mL = 6.1 mL
- Volume of the granite piece = 6.1 mL
Given that one cubic centimeter is equal to one mililiter, the volume of the granite piece in cm³ is 6.1 cm³.
