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jenyasd209 [6]
2 years ago
11

In the Ideal Gas Law lab, how is the temperature of the hydrogen gas determined?

Chemistry
1 answer:
grigory [225]2 years ago
5 0

In the ideal gas law, the temperature of the hydrogen gas determined if the volume and pressure of the gas is known.

The ideal gas law states that the pressure of ideal gas is directly proportional to the absolute temperature of the gas.

PV = nRT

where;

  • <em>P is the pressure of the gas</em>
  • <em>V is the volume of the gas</em>
  • <em>n is the number of moles of the gas</em>
  • <em>T is the temperature of the gas</em>

The temperature of the gas is determined as follows;

T = \frac{PV}{nR}

Thus, we can conclude that in the ideal gas law, the temperature of the hydrogen gas determined if the volume and pressure of the gas is known.

Learn more here:brainly.com/question/24542515

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When a strong base reacts with an acid what is always produced?
Y_Kistochka [10]
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3 years ago
If 1.2 moles of ideal gas occupy a volume of 18.2 L at a pressure of 1.8 ATM what is the temperature of gas in degrees Celsius.
Novosadov [1.4K]

Answer: A 59.5 degree celcius

The equation that we will use to solve this problem is :

PV = nRT where:

P is the pressure of gas = 1.8 atm

V is the volume of gas = 18.2 liters

n is the number of moles of gas = 1.2 moles

R is the gas constant =  0.0821

T is the temperature required (calculated in kelvin)

Using these values to substitute in the equation, we find that:

(1.8)(18.2) = (1.2)(0.0821)(T)

T = 332.5 degree kelvin

The last step is to convert the degree kelvin into degree celcius:

T = 332.5 - 273 = 59.5 degree celcius

8 0
3 years ago
What is the study of matter and it's changes.??
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5 0
3 years ago
When planning a simple experiment, what does it mean to “test one variable”?
SSSSS [86.1K]

Answer:

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Explanation:

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3 0
2 years ago
In a single displacement reaction between Sodium Phosphate and Barium, how much of each product (in grams) will be formed from 1
mixer [17]

Answer:

14.6 g of barium phosphate

3.35 g of sodium metal

Explanation:

2Na3PO4(aq) + 3Ba(s) -------> Ba3(PO4)2(aq) + 6Na(s)

The first step in any such reaction is to but down the balanced reaction equation according to the stoichiometry of the reaction.

The two products formed are barium phosphate and sodium metal.

Number of moles of barium corresponding to 10.0g of barium = mass of barium/ molar mass of barium

Molar mass of barium = 137.327 g

Number of moles of barium = 10/137.327

Number of moles of barium = 0.0728 moles

For barium phosphate;

3 moles of barium yields 1 mole of barium phosphate

0.0728 moles yields 0.0728 moles × 1/3 = 0.0243 moles of barium phosphate

Molar mass of barium phosphate = 601.93 g/mol

Therefore mass of barium phosphate = 0.0243 moles × 601.93 g/mol = 14.6 g of barium phosphate

For sodium metal

3 moles of barium yields 6 moles of sodium metal

0.0728 moles of barium yields 0.0728 × 6 / 3 = 0.1456 moles of sodium

Molar mass of sodium metal= 23 gmol-1

Mass of sodium metal= 0.1456g × 23 gmol-1 = 3.35 g of sodium metal

4 0
3 years ago
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