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jenyasd209 [6]
2 years ago
11

In the Ideal Gas Law lab, how is the temperature of the hydrogen gas determined?

Chemistry
1 answer:
grigory [225]2 years ago
5 0

In the ideal gas law, the temperature of the hydrogen gas determined if the volume and pressure of the gas is known.

The ideal gas law states that the pressure of ideal gas is directly proportional to the absolute temperature of the gas.

PV = nRT

where;

  • <em>P is the pressure of the gas</em>
  • <em>V is the volume of the gas</em>
  • <em>n is the number of moles of the gas</em>
  • <em>T is the temperature of the gas</em>

The temperature of the gas is determined as follows;

T = \frac{PV}{nR}

Thus, we can conclude that in the ideal gas law, the temperature of the hydrogen gas determined if the volume and pressure of the gas is known.

Learn more here:brainly.com/question/24542515

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Options are as follow,

1)  Flashes
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Answer:
            Option-3 (stretches) is the correct answer.

Explanation:
                    The best analogy which suits a chemical bond is the stretching of chemical bonds. Remaining verbs doesn't explain the property of chemical bond. For example, the chemical bonds did not flashes, neither they skip or jump.
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3 years ago
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A 25.0 ml sample of 0.150 m benzoic acid is titrated with a 0.150 m naoh solution. what is the ph at the equivalence point? the
Ad libitum [116K]

Solution:

At the equivalence point, moles NaOH = moles benzoic acid  

HA + NaOH ==> NaA + H2O where HA is benzoic acid  

At the equivalence point, all the benzoic acid ==> sodium benzoate  

A^- + H2O ==> HA + OH- (again, A^- is the benzoate anion and HA is the weak acid benzoic acid)  

Kb for benzoate = 1x10^-14/4.5x10^-4 = 2.22x10^-11  

Kb = 2.22x10^-11 = [HA][OH-][A^-] = (x)(x)/0.150  

x^2 = 3.33x10^-12  

x = 1.8x10^-6 = [OH-]  

pOH = -log [OH-] = 5.74  

pH = 14 - pOH = 8.26  


5 0
3 years ago
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if 100. mL of 0.800 M Na2SO4 is added to 200. mL of 1.20 M NaCl, what is the concentration of Na+ ions in the final solution? As
Black_prince [1.1K]
Compounds Na₂SO₄ and NaCl are mixed together are we are asked to find the concentration of Na⁺ in the mixture 
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1 mol of Na₂SO₄ gives out 2 mol of Na⁺ ions 

the number of Na₂SO₄ moles added - 0.800 M/1000 * 100 ml
                                                         = 0.08 mol
therefore number of Na⁺ ions from Na₂SO₄ = 0.08 * 2 = 0.16 mol

NaCl ----> Na⁺ + Cl⁻ 
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5 0
3 years ago
Can you find the error?<br> MgOH2
Ira Lisetskai [31]

The error is in the formula is bracket so the correct is Mg(OH)₂

The incorrect or error in the formula is bracket that would be that the compound contain only 1Mg atom and 1 oxygen atom and 2 hydrogen atom but is wrong when you write it in an electron dot diagram you will see that it is wrong there be unshared paired of electron and the correct formula is Mg(OH)₂

Know more about Mg(OH)₂

brainly.com/question/2597872

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