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Ber [7]
2 years ago
15

If 23.5 g of ammonia (NH3) is dissolved in 1.0 L of solution, what is the molarity?

Chemistry
1 answer:
r-ruslan [8.4K]2 years ago
4 0

Answer:

1.38 M

Explanation:

Need to use the Molarity equation M=n/L

23.5g/ 17.031g/mol NH3 = 1.38 moles

1.38 moles/ 1.0 L = 1.38 M

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No pressure but anyone who can answer these is a genius. (Please fill in the question mark)
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use variable

1K₂MnF₆ + aSbF₅⇒ bKSbF₆ + cMnF₃ + dF₂

K, left=2,right=b⇒b=2

Mn, left=1, right=c⇒c=1

Sb, left=a, right=b⇒a=b=2

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equation:

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So the reaction equation becomes:

1K₂MnF₆ + 2SbF₅⇒ 2KSbF₆ + 1MnF₃ + 0.5F₂ x2

2K₂MnF₆ + 4SbF₅⇒ 4KSbF₆ + 2MnF₃ + F₂

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2 years ago
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