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Ber [7]
2 years ago
15

If 23.5 g of ammonia (NH3) is dissolved in 1.0 L of solution, what is the molarity?

Chemistry
1 answer:
r-ruslan [8.4K]2 years ago
4 0

Answer:

1.38 M

Explanation:

Need to use the Molarity equation M=n/L

23.5g/ 17.031g/mol NH3 = 1.38 moles

1.38 moles/ 1.0 L = 1.38 M

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C. H2O

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True or False ? Endothermic reactions are characterized by net absorption of thermal energy from its surroundings which leads to
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Which of these formulas is NOT consistent with the guidelines for creating ionic compounds? Mark all that apply.
iVinArrow [24]

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d

Explanation:

because boron and fluorine are both nonmetals and don't fit the guidlelines for creating ionic compounds

8 0
3 years ago
How many 20.0-g ice cubes are required to absorb 47.0 kJ from a glass of water upon melting?
Sati [7]

Hello!


The number of 20-g ice cubes required to absorb 47 kJ from a glass of water upon melting is 7 icecubes


Why?


We are going to clear from the equation of the released heat, the mass of ice (m). The specific latent heat of fusion of ice is 336 kJ/kg:


Q=m*L\\ \\ m=\frac{Q}{L}=\frac{47 kJ}{336 kJ/kg}=0,1399 kg=139,88 g\\   \\ 139,88g*\frac{1 icecube}{20g}=6,99=7icecubes


So, 7 ice cubes are required to absorb that amount of heat from the glass of water.


Have a nice day!

3 0
3 years ago
A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added, and the
BARSIC [14]

Answer:

Rb+

Explanation:

Since they are telling us that the equivalence point was reached after 17.0 mL of   2.5 M HCl were added , we can calculate the number of moles of HCl which neutralized our unknown hydroxide.

Now all the choices for the metal cation are monovalent, therefore the general formula for our unknown is XOH and  we know the reaction is 1 equivalent acid to 1 equivalent base. Thus we have the number of moles, n,  of XOH and from the relation n = M/MW we can calculate the molecular weight of XOH.

Thus our calculations are:

V = 17.0 mL x 1 L / 1000 mL = 0.017 L

2.5 M HCl x 0.017 L = 2.5 mol/ L x 0.017 L = 0.0425 mol

0.0425 mol = 4.36 g/ MW XOH

MW of XOH = (atomic weight of X + 16 + 1)

so solving the above equation we get:

0.0425 = 4.36 / (X + 17 )

0.7225 +0.0425X = 4.36

0.0425X = 4.36 -0.7225 = 3.6375

X = 3.6375/0.0425 = 85.59

The unknown alkali is Rb which has an atomic weight of 85.47 g/mol

6 0
3 years ago
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