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Travka [436]
4 years ago
10

A bridge that was 5.0 m long has been washed out by the rain several days ago. How fast must a car be going to successfully jump

the stream? Although the road is level on both sides of the bridge, the road on the far side is 2.0 m lower than the road on this side. Group of answer choices
Physics
1 answer:
amid [387]4 years ago
8 0

Answer:

Speed, v = 7.83 m/s

Explanation:

It is given that,

Length of the bridge, l = 5 m

The road on the far side is 2.0 m lower than the road on this side, x = 2 m

The horizontal distance covered by the car is 5 meters and the vertical distance covered by the car is 2 meters.

Initial speed of the car, u = 0

Let t is the time taken by the car . Using the second equation of motion as :

For vertical distance :

s=ut+\dfrac{1}{2}gt^2

t=\sqrt{\dfrac{2\times 2}{9.8}}=0.638\ s

Let v is the velocity to jump the stream. It is given by :

Horizontal distance, d = 5 m

v=\dfrac{5\ m}{0.638\ s}

v = 7.83 m/s

So, the car should travel with a speed of 7.83 m/s. Hence, this is the required solution.

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A charge q produces an electric field of strength 4E at a distance of d away. Determine the electric field strength at a distanc
gizmo_the_mogwai [7]

Answer:

c.) 36E

Explanation:

The magnitude of the electric field is given by the expression

E=k \frac{q}{d^2} (1)

where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.

In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as

4E = k\frac{q}{d^2}

Now we want to determine the electric field at a distance of d'=\frac{1}{3}d away. Substituting into (1), we find

E' = k \frac{q}{d'^2}=k \frac{q}{(\frac{1}{3}d)^2}=9 k \frac{q}{d^2} (2)

We also know that

4E = k\frac{q}{d^2} (3)

So combining (2) with (3), we find a relationship between the original field and the new field:

E' = 9 \cdot (4E) = 36E

7 0
3 years ago
Andrew gets on his bike and begins riding.
crimeas [40]

Answer:

Push

Explanation:

Because the back tyre pushes you towards the road.

hope this helps

6 0
3 years ago
If the number of homes with a pet dog is equal to 250, how many total homes are repersented by the chart?
scoray [572]
500 because 250 x 2 = 500
3 0
4 years ago
Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up to
SIZIF [17.4K]

Answer:

5 m/s^2

Explanation:

The acceleration of the train is given by:

a=\frac{v-u}{t}

where:

u = 5 m/s is the initial velocity of the train

v = 45 m/s is the final velocity of the train

t = 8 s is the time taken for the train to increase the velocity

Substituting numbers into the formula, we find

a=\frac{45 m/s-5 m/s}{8 s}=5 m/s^2

5 0
4 years ago
Read 2 more answers
Suppose the maximum safe intensity of microwaves for human exposure is taken to be 1.39~\mathrm{W/m^2}1.39 W/m ​2 ​​ . If a rada
wolverine [178]

Answer:

0.763 m

Explanation:

Intensity I = power P ÷ area A of exposure (spherical area of propagation)

I = P/A

A = P/I

Power = 10.0 W

Intensity = 1.39 W/m^2

A = 10/1.39 = 7.19 m^2

Area A = 4¶r^2

7.19 = 4 x 3.142 x r^2

7.19 = 12.568r^2

r^2 = 7.19/12.568 = 0.57

r = 0.753 m

3 0
3 years ago
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