All categories

3 years ago

Which of the following natural factors is likely to support the formation of an oceanic island?

Physics

2 answers:

Evgen [1.6K]3 years ago

5 0

Answer: C ; Rising magma from the seafloor.

Explanation:

Underwater volcanoes erupting can cause the magma to rise above the seafloor therefor hardening and eventually creating islands. Upon this factor, you might know that another word for an oceanic island is a volcanic island, this is important to remember so that when you see a question like this one you will automatically know the answer without having to checkback.

stepan [7]3 years ago

4 0

The natural factor that is most likely to support the formation of an oceanic island is the rise of magma from the seafloor. Oceanic islands are also otherwise known as volcanic islands. When volcanoes erupt, they create layers of lava that break the surface of the water. When the tops of the volcanoes emerge, an island is created.

You might be interested in

Which of the following calls one might hear a refree make?

mestny [16]

Answer: D) All of the above

Explanation:

7 0

2 years ago

Read 2 more answers

Can you give me the definition of sound wave

katrin [286]

A sound wave is a wave of compression and rarefaction, by which sound is propagated in an elastic medium such as air.

3 0

3 years ago

Read 2 more answers

What happens to the gravitational potential energy between two particles if the distance between them is halved? (a) It does not

mr_godi [17]

Answer:

The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).

Explanation:

The gravitational force is the force of mutual attraction that two objects with mass experience.

The Law of Universal Gravitation enunciated by Newton says that every material particle attracts any other material particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically this is expressed as:

$F=G*\frac{m1*m2}{r^{2} }$

where m1 and m2 are the masses of the objects, r the distance between them and G a universal constant that receives the name of constant of gravitation.

If the distance between two particles is reduced by half, then, where F' is the new value of the gravitational force:

$F'=G*\frac{m1*m2}{(\frac{r}{2} )^{2} }$

$F'=G*\frac{m1*m2}{\frac{(r )^{2} }{2^{2} } }$

$F'=G*\frac{m1*m2}{\frac{(r )^{2} }{4} }$

$F'=4*G*\frac{m1*m2}{r^{2} }$

F'=4*F

The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).

7 0

3 years ago

John decided to cycle to his friend's house at a speed of 5km/h and the journey took 2

Marianna [84]

Answer:100 miles

Explanation:

5 0

3 years ago

Read 2 more answers

Hans Langseth's beard measured 5.33 m in 1927. Consider two charges, q1 = 2.42 nC and an unspecified charge, q2, are separated 5

schepotkina [342]

Answer:

-7.89 * 10^(-9) C

Explanation:

Parameters given:

q1 = 2.42 nC = 2.42 * 10^(-9) C

Distance between q1 and q2 = 5.33 m

q3 = 1.0 nC = 1 * 10^(-9) C

Distance between q1 and q3 = 1.9 m

Distance between q2 and q3 = 5.33 - 1.9 = 3.43 m

The net force acting on q3 is:

F = F(q1, q3) + F(q2, q3)

F = (k*q1*q3)/1.9² + (k*q2*q3)/3.43²

F = (9 * 10^(9) * 2.42 * 10^(-9) * 1 * 10^(-9))/3.61 + (9 * 10^(9) * q2 * 1 * 10^(-9))/11.7649

F = 6.033 * 10^(-9) + 0.765*q2

If the net force is zero:

0 = 6.033 * 10^(-9) + 0.765*q2

-0.765*q2 = 6.033 * 10^(-9)

=> q2 = -[6.033 * 10^(-9)]/0.765

q2 = -7.89 * 10^(-9) C

3 0

2 years ago