Question

Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?

Answer 1

Answer:

b

Explanation:

Answer 2

Answer:

$5 m/s^2$

Explanation:

The acceleration of the train is given by:

$a=\frac{v-u}{t}$

where:

u = 5 m/s is the initial velocity of the train

v = 45 m/s is the final velocity of the train

t = 8 s is the time taken for the train to increase the velocity

Substituting numbers into the formula, we find

$a=\frac{45 m/s-5 m/s}{8 s}=5 m/s^2$