Answer:
Explanation:
For spring
where n is frequency of oscillation and k is force constant and m is mass
Putting the values
k = .4032 N/m
F= k x
where F is force , k is force constant and x is extension
Putting the given values
1 = .4032 x
x = 2.48 m
- Weight = (mass) x (gravity)
6.86 N = (mass) x (9.8 m/s²)
Mass = (6.86 N) / (9.8 m/s²)
Mass = (6.86 kg-m/s²) / (9.8 m/s²)
Mass = (6.86/9.8) kg
Mass = 0.7 kilogram
<em>I would use the 500-gram weight and the 200-gram weight,</em> and hang them both from the end of the thread. Then the total mass on the end of the thread is 700 grams. When I take it to Earth, it will weigh 6.86 N .
Answer:
A:- 50 J
B:- 500 J
Explanation:
a) Given that a 25 N force is applied to move the box. Also the floor is having friction surface.
So in order to move the box, the floor should have friction of atleast 25 N.
∴ friction = 25 N
Work done = force * displacement of box
Given, the box is moved 2 m across the floor
So, Work done = friction * 2 m
= 25 * 2
= 50 J
b) Given, the box is having weight of 250 N weight
Gravitational force is acting on the box which is equal to (mass * gravity)
∴ Force = 250 N
The box is lifted 2 m above the floor.
So, displacement = 2 m
Work done = force * displacement of box
Work done = 250 * 2
= 500 J
Let's assume that the coordinate system is defined as positive in the first quadrant.
The system has its origin in the place where Ingrid kicks the football ball.
We have then that the horizontal component is given by:
Rewriting we have:
Rounding the obtained result we have:
Answer:
The horizontal component of the initial velocity to the nearest tenth is:
Explanation:
Given that,
Two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 570 N/C.
We need to find their speeds after 47.6 ns.
For electron,
The electric force is given by :
Let a be the acceleration of the electron. So,
F = ma
m is mass of electron
Let v be the final velocity of the electron. So,
v = u +at
u = 0 (at rest)
So,
For proton,
Acceleration,
Now final velocity of the proton is given by :
Hence, this is the required solution.