Answer:
1, 1583.33 V/m
2, 4.72*10^-12 C
3, 39.2*10^-11 C
Explanation:
1
E = V / d
E = 8.55 / 5.4*10^-3
E = 8.55 / 0.0054
E = 1583.33 V/m
2
Capacitance, C = (k * e0 * A) / d, where k = 1
A = area of capacitor, 3.37 cm² = 3.37*10^-4 m²
d = plate separation, 5.4 mm
e0 = Constant, 8.85*10^-12
Applying these, we have
C = (1 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3
C = 29.82*10^-16 / 0.0054
C = 5.52*10^-13 F
Since Q = CV, then
Q = 5.52*10^-13 * 8.55
Q = 4.72*10^-12 C
3
We are given that k = 83, so
Capacitance, C = (k * e0 * A) / d
C = (83 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3
C = 2.475*10^-13 / 0.0054
C = 4.58*10^-11 F
Q = CV
Q = 4.58*10^-11 * 8.55
Q = 39.2*10^-11 C
Newton's law is all about motion
CORRECT ANSWER:
a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.
STEP-BY-STEP EXPLANATION:
The complete question from book is
According to Figure 9.6, what is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?
a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.
b- Signaling molecules that bind to cell-surface receptors lead to cellular responses restricted to the cytoplasm; signaling molecules that bind to intracellular receptors lead to cellular responses restricted to the nucleus.
c- Cell-surface receptors bind to specific signaling molecules; intracellular receptors bind any signaling molecule.
d- Cell-surface receptors typically bind to signaling molecules that are smaller than those bound by intracellular receptors.
e- None of the other answer options is correct.
