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Makovka662 [10]
3 years ago
8

A pet store has three fish tanks, each holding a different volume of water and a different number of fish. Tank AAA holds 40\tex

t{ L}40 L40, start text, space, L, end text and 555 fish. Tank BBB holds 100\text{ L}100 L100, start text, space, L, end text and 121212 fish. Tank CCC holds 180\text{ L}180 L180, start text, space, L, end text and 232323 fish. Order the tanks by volume per fish from least to greatest.
Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

C, A and B

Step-by-step explanation:

Tank A holds 40 Liters and 5 fish.

  • Volume per fish of Tank A =40 \div 5 =$ 8 fish per liter

Tank B holds 100 Liters and 12 fish.

  • Volume per fish of Tank B =100 \div 12 =$ 8.33 fish per liter

Tank C holds 180 Liters and 23 fish.

  • Volume per fish of Tank C =180 \div 23 =$ 7.83 fish per liter

Therefore, the volume per fish from least to greatest is:

7.83, 8 and 8.33

These correspond to the tanks: C, A and B respectively.

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Two integers a and b have a product of -33. What is the least possible sum of a and b
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The number -33 divisors are:

D(-33) = {-33, -11, -3, -1, 1, 3, 11, 33}

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<u>1)  -33 × 1 = -33   ⇒   Sum is:   -33 + 1 = -32</u>

2)  -11 × 3 = -33   ⇒   Sum is:   -11 + 3 = -8

3)  -3 × 11 = -33   ⇒   Sum is:   -3 + 11 = 8

4)  -1 × 33 = -33   ⇒   Sum is:   -1 + 33 = 32

<u>5)  1 × (-33) = -33   ⇒   Sum is:   1 + (-33) = 1 - 33 = -32</u>

6)  3 × (-11) = -33   ⇒   Sum is:   3 + (-11) = 3 - 11 = -8

7)  11 × (-3) = -33   ⇒   Sum is:   11 + (-3) = 11 - 3 = 8

8)  33 × (-1) = -33   ⇒   Sum is:   33 + (-1) = 33 - 1 = 32

<h2>The least possible sum of a and b is  -32</h2>

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