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3 years ago

10

PLEASE SOLVE THIS EQUATION

1 answer:

Masteriza [31]3 years ago

3 0

The measure of angle 6 is 84 :)

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Plz help first to answer gets 50 points

djverab [1.8K]

D is the correct answer bc the 3’s continue forever

5 0

2 years ago

Read 2 more answers

What is the value of f?<br><br> 6f−12=−4f+6

Xelga [282]

First you had to add by twelve from both sides of equation form.

$6f-12+12=-4f+6+12$

Then simplify.

$6f=-4f+18$

Next, add by four-f from both sides of equation form.

$6f+4f=-4f+18+4f$

Simplify.

$10f=18$

Then you divide by ten from both sides of equation form.

$\frac{10f}{10}= \frac{18}{10}$

Finally simplify by equation.

$f=\frac{9}{5}$

Final answer: $\boxed{f=9/5}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

3 0

3 years ago

Use the definition of continuity to determine whether f is continuous at a. f(x) = 5x+5 a = -5 Question

Andrej [43]

ANSWER

$lim_{x \to - 5}(f(x)) = f( - 5)$

EXPLANATION

If f(x) is continuous at

$x = a$

Then,

$lim_{x \to a}(f(x)) = f(a)$

The given function is

$f(x) = 5x + 5$

$f( - 5) = 5( - 5) + 5$

$f( - 5) = - 25 + 5 = - 20$

$lim_{x \to - 5}(f(x)) = 5( - 5) + 5$

$lim_{x \to - 5}(f(x)) = - 20$

Since,

$lim_{x \to - 5}(f(x)) = f( - 5)$

The function is continuous at

$x = - 5$

4 0

3 years ago

Read 2 more answers

Please help me. I will give you brainliest!

Dvinal [7]

Answer:

50 6 300

10 2 20

Step-by-step explanation:

3 0

3 years ago

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A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0

2 years ago