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Rudik [331]
3 years ago
10

PLEASE SOLVE THIS EQUATION

Mathematics
1 answer:
Masteriza [31]3 years ago
3 0
The measure of angle 6 is 84 :)
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Plz help first to answer gets 50 points
djverab [1.8K]
D is the correct answer bc the 3’s continue forever
5 0
2 years ago
Read 2 more answers
What is the value of f?<br><br> 6f−12=−4f+6
Xelga [282]

First you had to add by twelve from both sides of equation form.

6f-12+12=-4f+6+12

Then simplify.

6f=-4f+18

Next, add by four-f from both sides of equation form.

6f+4f=-4f+18+4f

Simplify.

10f=18

Then you divide by ten from both sides of equation form.

\frac{10f}{10}= \frac{18}{10}

Finally simplify by equation.

f=\frac{9}{5}

Final answer: \boxed{f=9/5}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie



3 0
3 years ago
Use the definition of continuity to determine whether f is continuous at a. f(x) = 5x+5 a = -5 Question
Andrej [43]

ANSWER

lim_{x \to  - 5}(f(x))  = f( - 5)

EXPLANATION

If f(x) is continuous at

x = a

Then,

lim_{x \to a}(f(x))  = f(a)

The given function is

f(x) = 5x + 5

f( - 5) =  5( - 5) + 5

f( - 5) =  - 25 + 5 =  - 20

lim_{x \to  - 5}(f(x))  = 5( - 5) + 5

lim_{x \to  - 5}(f(x))  =  - 20

Since,

lim_{x \to  - 5}(f(x))  = f( - 5)

The function is continuous at

x =  - 5

4 0
3 years ago
Read 2 more answers
Please help me. I will give you brainliest!
Dvinal [7]

Answer:

50            6                   300

10               2                  20

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000
Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

p_1=X_1/n_1=494/1000=0.494

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

p_2=X_2/n_2=552/1000=0.552

The difference between proportions is (p1-p2)=-0.058.

p_d=p_1-p_2=0.494-0.552=-0.058

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022

Then, the margin of error is:

MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0
2 years ago
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