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nirvana33 [79]
3 years ago
13

Which is the simplified form of r^-7 + s^-12? arrows to the left of -7 and -12 represent exponents,

Mathematics
2 answers:
polet [3.4K]3 years ago
7 0

a^{-b}=\dfrac{1}{a^b}\\\\ r^{-7}+s^{-12}=\dfrac{1}{r^7}+\dfrac{1}{s^{12}}\implies \text{D}

Marrrta [24]3 years ago
3 0

Answer is D, 1/r^7 + 1/s^12. Im positive 100%

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The nth term of a sequence is 25-3n
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Answer:

22, 19, 16 and - 5

Step-by-step explanation:

To evaluate any term from the n th term formula substitute the terms position value for n

given a_{n} = 25 - 3n, then

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a_{1} = 25 - (3 × 1) = 25 - 3 = 22

a_{2} = 25 - (3 × 2) = 25 - 6 = 19

a_{3} = 25 - (3 × 3) = 25 - 9 = 16

(b)

a_{10} = 25 - (3 × 10) = 25 - 30 = - 5


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Standard form: -3x +5y= -1
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Is this even possible?
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Mister Rogers is fencing another new rectangular garden in his neighborhood. One side of the garden faces the road and needs to
Oksanka [162]

Answer:

length of the pretty side  and length of the side oppositte to the pretty side  =   37.91 ft

length of the other two sides  = 27.52 ft

Step-by-step explanation:

The mathematical problem is:

Max A = b1*h

subject to: 35*b1 + 18*(2*h + b2) <= 3000

Where

A: area of the garden

b1: length of the pretty side

b2: length of the side oppositte to the pretty side

h: length of the other two sides

Replacing with b1 = b2 and taking only the equality sign in the restriction (in the maximum all the money will be spent), we get:

35*b1 + 18*(2*h + b1) = 3000

35*b1 + 36*h + 18*b1 = 3000

53*b1 + 36*h = 3000

b1 = 3000/53 - (36/53)*h

Substituing in Area's formula  

A = (3000/53 - (36/53)*h)*h

A = (3000/53)*h - (36/53)*h^2

In the maximum, the derivative of A is equal to zero

dA/dh = 3000/53 - 2*(36/53)*h =

3000/53 - 72/35*h = 0

h = (3000/53)*(35/72)

h = 27.52 ft

then,

b1 = 3000/53 - (36/53)*27.52

b1 = 37.91 ft =b2

3 0
3 years ago
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