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White raven [17]
3 years ago
6

You lose 5 points for every wrong answer in a trivia game. What integer represents the change in your points after answering 8 q

uestions wrong?
Mathematics
1 answer:
Inessa05 [86]3 years ago
7 0
The answer to that is -40
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Use an appropriate half-angle formula to find the exact value of the expression. cos 3π 8
cricket20 [7]
The half-angle formula for cosine is
\cos{\left(\dfrac{\theta}{2}\right)}=\sqrt{\dfrac{1+\cos{\theta}}{2}}

To find cos(3π/8), we can use this formula with θ=3π/4. Cos(3π/4) = -(√2)/2, so we have

\cos{\left(\dfrac{3\pi}{8}\right)=\sqrt{\dfrac{1-\frac{\sqrt{2}}{2}}{2}}\\\\=\sqrt{\dfrac{2-\sqrt{2}}{4}}=\frac{1}{2}\sqrt{2-\sqrt{2}}
4 0
3 years ago
Help pleaseee and thankyouuuu
max2010maxim [7]

Answer:

C

Step-by-step explanation:

7*4*2 1/2

3 0
3 years ago
Solve the equation (Multi Step) and describe each step you use.<br> 11p - 4 = 6p + 1
Julli [10]

Answer:

p=1

Step-by-step explanation:

isolate the variable by dividing each side by factors that don't contain the variable.

4 0
3 years ago
Read 2 more answers
PLEASE HELPPPPP
Flauer [41]

Answer:

Cost of 1 rose bush = x = $5

Cost of 1 geraniums = y = $2

Step-by-step explanation:

DeShawn and Mike each improved their yards by planting rose bushes and geraniums. They bought their supplies from the same store.

Let us represent:

Cost of 1 rose bush = x

Cost of 1 geraniums = y

DeShawn spent $13 on 1 rose bush and 4 geraniums.

x + 4y = 13..... Equation 1

x = 13 - 4y

Mike spent $56 on 10 rose bushes and 3 geraniums.

10x + 3y = 56....... Equation 2

We substitute 13 - 4y for x in Equation 2

10(13 - 4y) + 3y = 56

130 - 40y + 3y = 56

Collect like terms

- 40y + 3y = 56 - 130

-37y = -74

y = -74/37

y = $2

Solving for x

x = 13 - 4y

x = _13 - 4 × $2

x = $13 - $8

x = $5

Therefore,

Cost of 1 rose bush = x = $5

Cost of 1 geraniums = y = $2

7 0
3 years ago
Wich measurements is not precise 982g or 980g
gavmur [86]

Answer:

982 g

Step-by-step explanation:

Hopefully this helps you :)

8 0
3 years ago
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