Am I correct?? HELP!!
1 answer:
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Answer:
i)D:
ii)R:
iii) Y-int:(0,-1)
Step-by-step explanation:
i) The given absolute value function is;
.
The absolute value function is defined for all real values of x.
The domain is all real numbers.
ii) The range is all y-values that will make x defined.
The given function,
.
has vertex at, (-2,-3) and opens upwards.
This implies that, the minimum y-value is -3.
The range is
iii) To find the y-intercept substitute x=0 in to the function.
.
.
.
.
The y-intercept is (0,-1)
See attachment for graph.
<h2>Answer:</h2>
<em> The side of the triangle is either 38.63ft or 10.35ft</em>
<h2>Step-by-step explanation:</h2>This problem can be translated as an image as shown in the Figure below. We know that:
- The side of the square is 10 ft.
- One of the vertices of an equilateral triangle is on the vertex of a square.
- Two other vertices are on the not adjacent sides of the same square.
Let's call:
Since the given triangle is equilateral, each side measures the same length. So:
x: The side of the equilateral triangle (Triangle 1)
y: A side of another triangle called Triangle 2.
That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:
We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:
Therefore, for Triangle 3, we have that by Pythagorean theorem:
Matching equations (1) and (2):
Using quadratic formula:
Finding x from (1):
<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>