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Alexeev081 [22]
3 years ago
12

A 1.525g sample of a compound between nitrogen and hydrogen contains 1.333 g of nitrogen. Calculate its empirical formula. The e

mpirical formula is?
Chemistry
1 answer:
vredina [299]3 years ago
5 0

Answer:

NH2.

Explanation:

The mass of hydrogen in the sample = 1.525 - 1.333 = 0.192g.

Dividing the 2 masses by the  relative atomic mass of hydrogen and nitrogen:

H: 0.192 / 1.008 = 0.1905

N: 1.333 / 14.007 = 0.09517

The ratio of N to H =  0.09517 : 0.1905

=  1 : 2.

So the empirical formula is  NH2.

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Increases in the amount of cytoplasmic calcium required to initiate a muscle contraction are mediated by the coupling between a
lesantik [10]

Answer:

1) Dihydropyridine receptor

2) Rynodine receptor

Explanation:

Rynodine receptor: It is a category of interacellular channels of calcium with different forms like neurons and muscles found in animal tissues.

Dihydropyridine receptor: they are present in muscle tissues and are able to sense voltage in skeleton muscles thus can increase or control the release of calcium.

4 0
3 years ago
T
svet-max [94.6K]

Explanation:

(1) The nucleus is positive and the electron cloud is positive.

(2) The nucleus is positive and the electron cloud is negative.

(3) The nucleus is negative and the electron cloud is positive.

(4) The nucleus is negative and the electron cloud is negative

4 0
3 years ago
23.495 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 72.311 g of wate
Otrada [13]

Answer:

1.86% NH₃

Explanation:

The reaction that takes place is:

  • HCl(aq) + NH₃(aq) → NH₄Cl(aq)

We <u>calculate the moles of HCl that reacted</u>, using the volume used and the concentration:

  • 32.27 mL ⇒ 32.27/1000 = 0.03227 L
  • 0.1080 M * 0.03227 L = 3.4852x10⁻³ mol HCl

The moles of HCl are equal to the moles of NH₃, so now we <u>calculate the mass of NH₃ that was titrated</u>, using its molecular weight:

  • 3.4852x10⁻³ mol NH₃ * 17 g/mol = 0.0592 g NH₃

The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:

  • 0.0592 / 12.949 * 100% = 0.4575%

Now we <u>calculate the total mass of NH₃ in the diluted sample</u>:

Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g

  • 0.4575% * 95.806 g = 0.4383 g NH₃

Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:

  • 0.4383 g NH₃ / 23.495 g * 100% = 1.86% NH₃

6 0
3 years ago
When potassium hydroxide and barium chloride react, potassium chloride and barium hydroxide are formed. The balanced equation fo
Mashcka [7]

Answer:

The answer to your question is letter C.

Explanation:

Reaction

Potassium hydroxide = KOH

Barium chloride = BaCl₂

Potassium chloride = KCl

Barium hydroxide = Ba(OH)₂

           KOH   +   BaCl₂    ⇒    KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               1                     K                      1

               1                     Ba                    1

               2                    Cl                     1  

                1                     H                    2

                1                     O                    2

The reaction is unbalanced

        2KOH   +   BaCl₂    ⇒   2KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               2                     K                     2

               1                     Ba                    1

               2                    Cl                     2  

               2                      H                    2

               2                     O                    2

Now, the reaction is balanced

7 0
3 years ago
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solmaris [256]
Soild , liquid, gas
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