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Drupady [299]
3 years ago
7

021.59 cmasdfghjkl;'`1234567890-erghjm

Chemistry
2 answers:
Zarrin [17]3 years ago
8 0

Answer:

yes

Explanation:

Sergeeva-Olga [200]3 years ago
6 0
Cmasdfghjkl;^2 I think

Lol hoped this helped
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Draw the products of the acid-base reaction between stearic acid and OH-
jok3333 [9.3K]

Answer:

Products are stearate anion and water.

Explanation:

Stearic acid is a 18-carbon chain molecule containing -COOH group. IUPAC name of stearic acid is octadecanoic acid.

Molecular formula of stearic acid is C_{17}H_{35}CO_{2}H.

When OH^{-} is added into stearic acid, OH^{-} removes a proton (H^{+}) from acidic -COOH group and forms stearate anion and water as products.

The balanced acid-base reaction is given as:

                  C_{17}H_{35}CO_{2}H+OH^{-}\rightleftharpoons C_{17}H_{35}CO_{2}^{-}+H_{2}O

Structure of products are given below.

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3 years ago
How many sigma bonds and pi bonds are in limonene
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6 sigma and 1 pi

Explanation:

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How does the magnetic field surrounding earth benefit humankind
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The density of concentrated ammonia, which is 28.0% w/w nh3, is 0.899 g/ml. what volume of this reagent should be diluted to 1.0
vlada-n [284]

Answer: 2.4 ml

Solution :

Molar mass of NH_3 = 17 g/mole

Given,: 28% w/w of NH_3 solution means 28 g of ammonia in 100 g of solution.

Mass of solution = 100 g

Now we have to calculate the volume of solution.

Volume=\frac{Mass}{Density}=\frac{100g}{0.899g/ml}=111.2ml  

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute NH_3=\frac{\text {given mass}}{\text {molar mass}}=\frac{28}{17}=1.65moles

V_s = volume of solution in liter = 0.11 L

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.65moles}{0.11L}=15mole/L

Using molarity equation:

M_1V_1=M_2V_2

15\times V_1=0.036\times 1.0\times 10^{3}

V_1=2.4ml

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3 years ago
Does Mg or Ne have a higher electronegativity value
elena55 [62]

Answer:

Ne

Explanation:

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3 years ago
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