Answer:
You would have 1.96 moles.
Explanation:
You are given 608 grams of calcium phosphate Ca₃(PO₄)₂.
Molar mass (M) is the amount of mass that a substance contains in one mole. This substance can be an element or a compound.
Since the molar mass of the compound Ca₃(PO₄)₂ is 310 g / mole, and taking into account the definition of molar mass, you can apply the following rule of three: if 310 grams of Ca₃(PO₄)₂ are contained in 1 mole, 608 grams of the compound in how many moles are present?
moles= 1.96
<u><em>You would have 1.96 moles.</em></u>
2-7-18-7 because selenium atom would have a total of <span>a total of 34 electrons. Hope this helps!!</span>
Answer:
108.3g
Explanation:
Given parameters:
Volume of solution = 570mm = 0.57L (1000mm = 1L)
Molarity of solution = 2M
Unknown
Mass of MgCl₂
Solution
We first find the number of moles in the given concentration of magnessium chloride using the expression below:
Number of moles of MgCl₂= Molarity x volume = 2 x 0.57 = 1.14moles
Using this known moles, we can the unknown mass of MgCl₂ the technician would require:
Mass of MgCl₂ required = number of moles of MgCl₂ x molar mass
Molar mass of MgCl₂:
Atomic mass of Cl = 35.5g
Atomic mass of Mg = 24g
MgCl₂ = 24 + (35.5x2) = 95gmol⁻¹
Mass of MgCl₂ required = 1.14mole x 95gmole⁻¹ = 108.3g
Answer:
D evaportaion. it shows the sun evaporating the lake.
