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3 years ago

Am i correct?????????????????????????????

Chemistry

2 answers:

AleksandrR [38]3 years ago

8 0

Answer:

yep you are correct.

Explanation:

Zolol [24]3 years ago

7 0

Yes this looks correct to me.

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9. Ibuprofen contain which of the following two functional groups: (1 point)

stira [4]

Answer:

A and C

I hope this helps you:)

4 0

3 years ago

Draw the structure of 1,4-hexanediamine.

brilliants [131]

Answer:

1,4-hexanediamine contains two $-NH_{2}$ functional groups.

Explanation:

1,4-hexanediamine is an organic molecule which contains two $-NH_{2}$ functional groups at C-1 and C-4 position.

The longest carbon chain in 1,4-hexanediamine contains six carbon atoms.

Molecular formula of 1,4-hexanediamine is $C_{6}H_{16}N_{2}$ .

1,4-hexanediamine used as a bidentate ligand in organometallic chemistry.

The structure of 1,4-hexanediamine is shown below.

5 0

3 years ago

Three quantum numbers for an electron in a hydrogen atom in a certain state are

OLga [1]

It is option A 4s cause n=4, l=1 this is 4s orbital

6 0

3 years ago

Which relationship or statement best describes delta s for the following reaction:

zalisa [80]

Answer:

b) Delta S < 0

Explanation:

The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn(g) = n(g, products) - n(g, reactants).

If Δn(g) > 0, the entropy increases (ΔS > 0).

If Δn(g) < 0, the entropy decreases (ΔS < 0).

If Δn(g) = 0, there is little or no change in the entropy

Let's consider the following equation.

2 H₂S(g) + 3 O₂(g) → 2 H₂O(g)

Δn(g) = 2 - 5 = - 3. Since Δn(g) < 0, the entropy decreases and ΔS < 0.

4 0

3 years ago

How many grams of phosphorus are in 500.0 grams of calcium phosphide? (i need the work also)

kvv77 [185]

Answer:

$\boxed{\text{170.0 g P}}$

Explanation:

The formula of calcium nitride is Ca₃P₂.

The masses of each element are:

$\begin{array}{lrcr}\text{3Ca:} & 3 \times 40.08&=& \text{120.24 u}\\\text{2P:} & 2\times 30.97&=& \text{61.94 u}\\& \text{TOTAL} & = & \text{182.18 u}\\\end{array}$

So, there are 61.94 g of P in 182.18 g of Ca₃P₂.

In 500 g of Ca₃P₂:

$\text{Mass of P} = \text{500.0 g Ca$_{3}$P$_{2}$} \times \dfrac{\text{61.94 g P}}{\text{182.18 g Ca$_{3}$P$_{2}$}} = \text{170.0 g P}$

There are $\boxed{\textbf{170.0 g P}}$ in 500.0 g of Ca₃P₂.

3 0

3 years ago