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CaHeK987 [17]
3 years ago
13

NEED HELP ASAP (WILL MARK BRAINLYEST)

Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

2,4,5, and 6

Step-by-step explanation:

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Can someone please help me with this problem:(
Flauer [41]

Answer:

x y

-2 4

0 0

1 -2

2 4

Step-by-step explanation:

in the equation replace x with the number from the table in the x colum then complete the equation

7 0
3 years ago
What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)? 3 4 5 9
ICE Princess25 [194]

1.5(x+4)-3=4.5(x-2)

First, distribute 1.5 into x and 4, and 4.5 into x and -2, to get rid of the parentheses. Everything that we do to solve this equation is to isolate x to solve for its value.

1.5x+6-3=4.5x-9

Combine like terms on both sides (6-3).

1.5x+3=4.5x-9

Subtract 1.5x from both sides.

3=3x-9

Add 9 to both sides.

12=3x

Divide both sides by 3.

4=x

The answer is 4.

I hope this helps :)

7 0
3 years ago
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f is a quadratic function whose graph is a parabola opening upward and has a vertex on the x-axis. The graph of the new function
Dmitriy789 [7]
<span> Answer: ( - infinity , 2] 
No need to spam, it makes you lose your hard-earned points!</span>
4 0
3 years ago
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I have zero idea.. help please.
r-ruslan [8.4K]
As we look, line TU = 16. But, there are two lines right below it, and there are two lines on the line UW. Now, all that this means is UW is the same length as TU. 

Since we know what TU and UW is and we need to add them together to find the total length of the line TW.

16 + 16 = 32.

Therefore, the length of line TW is 32 units long.

Hope I could help you out!
If my answer is incorrect, or I provided an answer you were not looking for, please let me know. However, if my answer is explained well and correct, please consider marking my answer as Brainliest!  :)

Have a good one.
God bless!
8 0
3 years ago
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Demonstrate two different ways to solve the equation 5^(2x+1) = 25.
Tanzania [10]

Answer:

Step-by-step explanation:

Method 1: Taking the log of both sides...

So take the log of both sides...

5^(2x + 1) = 25

log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...

(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...

(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...

(2x)log 5 + log 5 - log 5 = log 25 - log 5

(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)

(2x)log 5 = log 5 <-- divide both sides by log 5

(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..

2x = 1

x=1/2

Method 2

5^(2x+1)=5^2

2x+1=2

2x=1

x=1/2

3 0
3 years ago
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