Step-by-step explanation:
hope it help you.
thanks.��
First lets see the pythagorean identities

So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is

Now we need to check the sign of sin theta
First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.
So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .
Answer:
200
Step-by-step explanation:
I did it in a different way I think but this is how I did it. ._.
100÷2=50
50×4=200
So we need to find the common multiples of 6 and 12. Which are basically the multiples of 12, since 6 is always divisible to 12. So (12, 24, 36, 48, 60, 72, 84, 96, 108) Since it is a factor of 108, we stop at 108 (since a number greater than 108 can't be a factor of 108)
Now we find the factors of 108
108=<span>1,2,3,4,6,9,12,18,27,36,54,108
The numbers in both lists are 36 and 108 but since Micah is thinking of a 2-digit number, the number she is thinking of is 36.</span>
Explanation:
The test grade for 1st three tests = 62, 85, 89
Let the fourth test score = x
The result we hoping to get is grade B.
Let's find the average of the four test score




This means Cassie needs to score 84 or more to get a grade of B
In ineq