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ElenaW [278]
3 years ago
10

Can someone please help me with this problem asap? Thanks!! :))

Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer: \$4.34

Step-by-step explanation:

We have the following information:

Fredburguer F, milkshake M and an order of fries f costs \$3.72:

F+M+f=\$3.72 (1)

One Fredburguer is equal to a milkshake plus orders of fries:

F=M+2f (2)

Three milshakes is equal to a Fredburguer plus an order of fries:

3M=F+f (3)

And we are asked: If we have a Fredburguer, a milkshake and two orders of fries, how much do we have to pay?

F+M+2f=x (4)

Well with the first three equations we have a system of equations to solve. Let's begin by isolating F from (3):

F=3M-f (5)

Making (2)=(5):

M+2f=3M-f (6)

Isolating f:

f=\frac{2}{3}M (7)

Substituting (7) in (2):

F=M+2(\frac{2}{3}M) (8)

Isolating F:

F=\frac{7}{3}M (9)

Substituting (7) and (9) in (1):

\frac{7}{3}M+M+\frac{2}{3}M=\$3.72 (10)

Isolating M:

M=\$0.93 (11) This is the cost of a Milkshake

Substituting (11) in (7):

f=\frac{2}{3}\$0.93 (12)

f=\$0.62 (13) This is the cost of an order of frieds

Substituting (11) in (9):

F=\frac{7}{3}\$0.93 (14)

F=\$2.17 (15) This is the cost of a Fredburguer

Substituting (11), (13) and  (15) in (4):

\$2.17+\$0.93+2(\$0.62)=x (16)

Finally:

x=\$4.34 This is the cost of a Fredburguer, a milkshake and two orders of fries

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============================================================

Explanation:

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The first equation to set up is r+c = 50.

This equation can be solved to get r = 50-c.

------------------

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So that works out. I have a feeling your teacher meant to say "70 orders" instead of "50 orders". If so, then the equation r+c = 50 would be r+c = 70 and everything would lead to choice B as the final answer.

Choices C and D are similar to that of choice A, so they can be ruled out.

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