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arlik [135]
4 years ago
13

How many moles of glucose, C6H12O6, can be burned when 60.0 mol of oxygen is available? C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l)

Chemistry
1 answer:
kiruha [24]4 years ago
6 0

60mol O2 × 1 mol C6H12O6 / 6 moles 02 = 10 moles of Glucose

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Photosynthesis in photic zone Edit

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follow me ok nice study ☺️☺️☺️

4 0
3 years ago
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