Calculate the work (kJ) done during a reaction in which the internal volume contracts from 85 L to 12 L against an outside press

Question

3 years ago

9

ure of 2.4 atm.

1 answer:

butalik [34] · Answer 1 · 2022-06-03T21:49:04+03:00

Answer:

The work done on the system is 17.75_KJ

Explanation:

To solve this question we need to know the required equations from the given variables, thus

Initial volume = 85L

Final volume = 12L

External pressure = 2.4 atm.

work done = - PΔV

2.4×(85-12) = 175.2L×atm

Converting from L•atm to KJ is given by

1 L•atm = 0.1013 kJ

(175.2 L•atm) * (0.1013 kJ / 1 L•atm)

= 17.75 kJ

The work done on the system is 17.75_KJ