Calculate the work (kJ) done during a reaction in which the internal volume contracts from 85 L to 12 L against an outside press
1 answer:
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The equilibrium constant for the reaction is 0.00662
Explanation:
The balanced chemical equation is :
2NO2(g)⇌2NO(g)+O2(g
At t=t 1-2x ⇔ 2x + x moles
The ideal gas law equation will be used here
PV=nRT
here n= =
= density
P = density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm
putting the values in reaction
0.75 =
M = 34.61
to calculate the Kc
Kc=
x M NO2 +
M NO+
M O2
Putting the values as molecular weight of NO2, NO,O2
34.61=
x= 0.33
Kc=
putting the values in the above equation
Kc = 0.00662