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nlexa [21]
3 years ago
15

A compound contains potassium, nitrogen, and oxygen. the experimental analysis gave values of 45.942 % potassium and 16.458 % ni

trogen, by weight, the remainder is oxygen. what is the empirical formula of the compound?
Chemistry
2 answers:
9966 [12]3 years ago
7 0
It should be KNO3 to the best of my understanding
Tanya [424]3 years ago
4 0

Answer:

KNO₂

Explanation:

To get the empirical formula of a compound, we follow a series of steps.

Step 1: Given data

%K = 45.942%

%N = 16.458%

%O = 100.000% - 45.942% - 16.458% = 37.600%

Step 2: Divide each percentage by the atomic mass of the element

K: 45.942 / 39.098 = 1.1750

N: 16.458 / 14.007 = 1.1750

O: 37.600 / 15.999 = 2.3501

Step 3: We divide all the coefficients by the smallest number

K: 1.1750 / 1.1750 = 1

N: 1.1750 / 1.1750 = 1

O: 2.3501 / 1.1750 = 2

The empirical formula is KNO₂.

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I believe the answer is C.
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If an unknown quantity of gas is held at a temperature of 789 K in a container with a volume of
Orlov [11]

Answer:

n = 0.34 mol

Explanation:

Given data:

Given temperature = 789 K

Pressure = 765 torr ( 765/760 = 1.0 atm

Volume of container = 22.0 L

Number of moles of gas = ?

Solution:

Formula:

PV = nRT

n = PV/RT

n = 1.0 atm × 22.0 L / 0.0821 atm.L/mol.K ×789 K

n = 22.0 L.atm /64.8 atm.L/mol

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8 0
3 years ago
Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.
Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O.

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O

Number of atoms present on reactant side are as follows.

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Number of atoms present on product side are as follows.

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To balance this equation, multiply O_{2} by 2 on reactant side. Also, multiply H_{2}O by 2 on product side. Hence, the equation can be rewritten as follows.

CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O

Now, the number of atoms present on reactant side are as follows.

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  • H = 4
  • O = 4

Number of atoms present on product side are as follows.

  • C = 1
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Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O.

4 0
3 years ago
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umka21 [38]

Answer:

why did you mention that you're a girl ~_~

Explanation:

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