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Alex17521 [72]
4 years ago
7

2a - 4b +3ab -5a +2b

Mathematics
2 answers:
DaniilM [7]4 years ago
6 0

Answer:

-3a-2b+3ab

Step-by-step explanation:

2a-5a

-4b+2b

Vesnalui [34]4 years ago
6 0

Answer:

3a+2b-3ab=0

Step-by-step explanation:

2a - 5a -4b+2b+3ab

-3a-2b +3ab

taking - common

-(3a+2b-3ab)=0

3a+2b-3ab=0

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I need help with this (don't answer if you don't know)
SashulF [63]

Answer:

Step-by-step explanation:

Here's a step by step tutorial on your calculator on how to do this.  

Hit "stat" then "1: Edit".  If there are numbers there, arrow up to highlight L1, or L2, or wherever there are numbers.  Hit "clear" then "enter" and the numbers will be gone.  In L1, enter the Practice throws values.  Press 3 then enter, then 12 then enter, then 6 then enter, etc. til all of them are in L1's column.  Then arrow over to L2 and do the same with entering all the Free Throw values.

When you're done, hit "stat" again, then arrow over once to "calc" and #4 should say LinReg.  That's a linear regression equation.  If you have a TI 83, just hit enter and you'll get the equation in the form y = mx + b.  If you have a TI 84 or 84+, you'll need to arrow down to the word "calculate" and then you'll see the equation.

One thing...if you have not turned your diagnostics on, you wont be able to see the coefficient of determination (the r-squared value).  To make sure it's on:

Hit 2nd, then 0.  You have opened up the catalog which lists every single thing your calculator can do in alphabetical order.  The hit the button UNDER the MATH button (x to the negative 1) and scroll down until you see "diagnosticsON" and hit enter twice.

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4 0
3 years ago
Anyone help me please Thank you
Olin [163]
I have to say the answer is C
4 0
3 years ago
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The cost of 24 bottles of water is $6. Which expression shows how to find the cost of 10 bottles of water?
yaroslaw [1]
So first you need to find out how much one water bottle cost. 
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Answer:

Option A, B and E

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Determinant = ad-bc

Let's look at the picture and solve all

<u><em>Option A)</em></u>

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=> a(0)-b(0)

=> 0-0

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<u><em>Option B) </em></u>

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<u><em>Option C)</em></u>

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=> \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So , it's determinant will be

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<u><em>Option D)</em></u>

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<u><em>Option E)</em></u>

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