Question

Find the value of x and y please

Answer 1

Answer:

$x = 7( \sqrt{2} + \sqrt{6} ) \\ y = 14 \sqrt{3}$

Answer 2

Answer:

The answer to your question is  x = $7\sqrt{2}$  and y = $14\sqrt{3}$

Step-by-step explanation:

To find x and y use trigonometric functions

- Find x

To find x use the trigonometric function cosine

       cosine Ф = adjacent side/hypotenuse

- Solve for adjacent side (x)

       x = hypotenuse x cos Ф      

- Substitution

      x = 14$\sqrt{2}$ cos 60

Simplification

      x = 14$\sqrt{2}$ (0.5)

      x = 7$\sqrt{2}$

- Find y

-Find the length of the opposite side of the small triangle

 Opposite side = sine Ф x hypotenuse

 Opposite side = 14$\sqrt{2}$ x sin 60

Opposte side = 14$\sqrt{2}$ ($\sqrt{3}$/2)

Opposite side = 7$\sqrt{6}$

- Find the length of y

 y = Opposite side/sin Ф    

 y = $7\sqrt{6}$ / $\sqrt{2} /2$

 y = 14$\sqrt{3}$