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3 years ago

Find the value of x and y please

Mathematics

2 answers:

Oksanka [162]3 years ago

8 0

Answer:

$x = 7( \sqrt{2} + \sqrt{6} ) \\ y = 14 \sqrt{3}$

Elden [556K]3 years ago

3 0

Answer:

The answer to your question is x = $7\sqrt{2}$ and y = $14\sqrt{3}$

Step-by-step explanation:

To find x and y use trigonometric functions

- Find x

To find x use the trigonometric function cosine

cosine Ф = adjacent side/hypotenuse

- Solve for adjacent side (x)

x = hypotenuse x cos Ф

- Substitution

x = 14 $\sqrt{2}$ cos 60

Simplification

x = 14 $\sqrt{2}$ (0.5)

x = 7 $\sqrt{2}$

- Find y

-Find the length of the opposite side of the small triangle

Opposite side = sine Ф x hypotenuse

Opposite side = 14 $\sqrt{2}$ x sin 60

Opposte side = 14 $\sqrt{2}$ ( $\sqrt{3}$ /2)

Opposite side = 7 $\sqrt{6}$

- Find the length of y

y = Opposite side/sin Ф

y = $7\sqrt{6}$ / $\sqrt{2} /2$

y = 14 $\sqrt{3}$

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