Answer: ((T/(2pi))^2)g
Step-by-step explanation: just solve for L
Answer:
If there are 1000 customers in the store one week, how many will purchase exactly one of these items
1000 CUSTOMERS*28%=280
Step-by-step explanation:
A The event that a persons buys a suit
B The event that a person buys a shirt
C The event that a person buys a tie
P(A)= 22%
P(B)= 30%
P(C)= 28%
P(AB)=
11%
P(AC)=
14%
P(BC)=
10%
P(ABC)=
6%
A u B u C Is the event that any item is bougth
AC u AC u BC Is the event that any two events occured
So the wanted probability is
P[(A u B u C )(AB u AC u BC)^c
P[(A u B u C )=P(AB)+ P(BC)+P(BC)
P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06
=0,51
0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c
=0,28
1000 CUSTOMERS*28%=280
Answer:
7
Step-by-step explanation:
n! Might be 7, and n might be 6. r might also be 6. So 6 - 6= 0! = 1
So I think it might be 7 ÷ 1, which is 7.
Answer:
a ^ 2 - b ^ 2 = ( a + b ) ( a - b ) where a = 4p and b = 3q.
( 4p + 3q ) ( 4p - 3q )
Answer:
-3.1, -3.2, -3.3, -3.4, -3.5, -3.6
Step-by-step explanation:
