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Sav [38]
4 years ago
15

What is the common name for sodium hypochlorite

Chemistry
1 answer:
Firlakuza [10]4 years ago
3 0
The common name is laundry bleach

Hope this helps
You might be interested in
Calculate the inner diameter of the steam tube between the boiler and the high pressure turbine if the average velocity of the s
stich3 [128]

Answer:

The inner diameter of the steam tube is 0.1185 m.

Explanation:

m=\rho \times A\times v=\frac{1}{V}\times A\times v

m = mass flow rate

\rho = density of the liquid

V=specific volume =\frac{1}{\rho }

v = velocity of the liquid

A = area of cross-section

Diameter of the cross-section = d = 2r

Given: m = 18 kg/s, v = 60 m/s,A=?, V = 0.036793 m^3/kg

18 kg/s=\frac{1}{0.036793 m^3/kg}\times A\times 60 m/s

A=0.0110379 m^2

Area of the inner cross section = \pi r^2=\pi \frac{d^2}{4}

\pi \frac{d^2}{4}=0.0110379 m^2

d = 0.1185 m

The inner diameter of the steam tube is 0.1185 m.

5 0
4 years ago
Alpha particles are most like...
gogolik [260]
They are identical to the nucleus of the helium-4 atom. So the answer is helium atoms.

Hope this helps! :)
4 0
4 years ago
What three tests must all theories pass to be considered a "proven" theory?
VladimirAG [237]

 In order to become a scientific theory the three categories that it must pass are the following: 


1) Can the phenomena be recreated in a laboratory setting? 


2) Can variables be changed, yet still result in like observations? 


3) Is the phenomena truly natural or was it the result of a man-made force enacting upon it?

7 0
4 years ago
A chemical reaction has two elements as reactants. Which type of reaction might occur?
Elden [556K]
That should be a synthesis reaction
3 0
3 years ago
Read 2 more answers
You mix 265.0 mL of 1.20 M lead(II) nitrate with 293 mL of 1.55 M potassium iodide. The lead(II) iodide is insoluble. What amoun
slava [35]

Answer:

105 grams PbI₂

Explanation:

Pb(NO₃)₂ + 2KI => 2KNO₃ + PbI₂(s)

moles Pb(NO₃)₂ = 0.265L(1.2M) = 0.318 mole

moles KI = 0.293(1.55M) = 0.454 mole => Limiting Reactant

moles PbI₂ from mole KI in excess Pb(NO₃)₂ = 1/2(0.454 mole) = 0.227 mol PbI₂

grams PbI₂ = 0.227 mol PbI₂ x 461 g/mole = 104.68 g ≈ 105 g PbI₂(s)

7 0
3 years ago
Read 2 more answers
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