Answer:
1.6 L is the volume of NaOH that has reacted
Explanation:
The balanced reaction is:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
This is a neutralization reaction between a strong acid and a strong base. The products are the correspond salt and water.
We propose this rule of three:
1 mol of sulfuric acid needs 2 mol of NaOH to react to react
Then, 2.4 moles of H₂SO₄ will react with (2.4 . 2) / 1 = 4.8 moles of NaOH
As molarity is 3M, we can determine the volume of our solution
Molarity (M) = mol / volume(L) → Volume(L) = mol / Molarity
Volume(L) = 4.8 mol / 3 M = 1.6 L
