Answer:
bottom left
Step-by-step explanation:
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May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer: Δx = 0.5
Step-by-step explanation:
We have the interval:
[−3, −1]
and we partition it into 4 equal intervals.
first, the range of our interval is equal to the difference between the extremes, this is:
-1 - (-3) = -1 + 3 = 2
Then, if we divide it into 4, we have 4 segments with a range of:
2/4 = 0.5
Then the subinterval delta is 0.5, and the 4 intervals are:
[−3, -2.5], [−2.5, −2], [−2, −1.5], [−1.5, −1]
Answer:
16
Step-by-step explanation:
Given
C=2r and r=8
So
C=2×8 (as r=8)
C=16 (ans)
Answer:
Step-by-step explanation:
eq. of directrix is y-1=0
let (x,y) be any point the parabola.
then\sqrt{ (x-6)^2+(y-2)^2}=\frac{y-1}{(-1)*2}
squaring
x²-12x+36+y²-4y+4=y²-2y+1
x²-12 x+40-1=4y-2y
2y=x²-12x+39=x²-12x+36+3
(x-6)²=2y-3