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astra-53 [7]
3 years ago
12

Ribbon is only sold by the spool. A spool contains 25 yards of ribbon. Shannon needs 58 yards of ribbon to wrap all the presents

which is equivalent to 2.32 spools how many spools should she buy
Mathematics
2 answers:
ella [17]3 years ago
6 0

Answer:

\boxed{\text{3 spools}}

Step-by-step explanation:

\text{1 spool =25 yd}\\\text{Spools needed } = \text{58 yd} \times \dfrac{\text{1 spool}}{\text{25 yd}} = \text{2.32 spools}\\\\\text{However, Shannon can't buy part of a spool. She must $\textbf{round up}$ to the next integer.}\\\text{Shannon must buy $\boxed{\textbf{3 spools}}$ of ribbon}

lubasha [3.4K]3 years ago
3 0

Answer:

1 spool.

Step-by-step explanation:

It is given in the question that 58.0 yards of ribbon equivalent to 2.32 spool.

We have to find number of spools Shannon will buy which will be equivalent to 25 yard ribbon.

∵ 58 yards of ribbon = 2.32 spool

∴ 1 yard of ribbon = \frac{2.32}{58} spool

∴ 25 yards of ribbon = \frac{2.32}{58} × 25

                                  = 1 spool

Therefore, Shannon will buy 1 spool.

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Mother wants to divide $36 between her daughters Ava and Charlotte in the ratio of their ages. If Ava is 15 years old and Charlo
Fantom [35]

Answer:

Ava's share = $20

Charlotte's share = $16

Step-by-step explanation:

15x + 12x = 36 : multiply each girl's age by same amount and adding gives $36

27x = 36 : add x terms

x = 36 / 27 : divide both sides of equation by 27

x = 4 / 3

Ava's share = 15x = 15 * 4/3 = 20

Charlotte's share = 12x = 12 * 4/3 = 16

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3 years ago
List all prime fractors of the composite number 50
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The factors of 50 are 1, 2, 5, 10, 25 and 50.<span> The factors of a number can be found by determining which numbers evenly divide into a given number.</span>
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3 years ago
PLZ HELP I WILL MARK BRAINLEST IF CORRECT
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they are equal or congruent because if you look at  it they both are right triangles

4 0
3 years ago
How do u find the slope of (6,-10), (-15,15)
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     y - y₁ = m(x - x₁)
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       - 10              - 10
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7 0
2 years ago
A factory worker productivity is normally distributed. one worker produces an average of 75 units per day with a standard deviat
Angelina_Jolie [31]
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
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Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
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5 0
3 years ago
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