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e-lub [12.9K]
3 years ago
11

Solve the following equation for x 10=2-4(ax-3)

Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

\large\boxed{x=\dfrac{1}{a}}

Step-by-step explanation:

2-4(ax-3)=10\qquad\text{subtract 2 from both sides}\\\\-4(ax-3)=8\qquad\text{divide both sides by (-4)}\\\\\dfrac{-4(ax-3)}{-4}=\dfrac{8}{-4}\\\\ax-3=-2\qquad\text{add 3 to both sides}\\\\ax-3+3=-2+3\\\\ax=1\qquad\text{divide both sides by}\ a\neq0\\\\x=\dfrac{1}{a}

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3 years ago
If the area of the blue square is 144 units2 and the area of the pink square is 1225 units2, then the length of the hypotenuse i
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Step-by-step explanation:

Blue=144units^2 This also works as the height of the triangle.

Pink=1225units^2 This also works as the base of the triangle.

Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.

To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.

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s=\sqrt[]{A}

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