What is (√2) + 2? (No decimals.)
1 answer:
You might be interested in
The best buy is from dealership B because dealership B has a lesser base price
<h3>The add-on options</h3>For the purpose of this exercise, the add-on options to select are:
- Sunroof
- Keyless entry
The total amount of the add-on options is:
Total = $500 + $1500
Total = $2000
<u>The inequality</u>
This is represented using:
Base price * (1 + Tax) + Fees + Add-on total ≤ 20000
So, we have:
(1 + 6.75%) * x + 751.56 + 2000 ≤ 20000
<u>Solve for x</u>
We have:
(1 + 6.75%) * x + 751.56 + 2000 ≤ 20000
Evaluate the like terms
(1 + 6.75%) * x ≤ 17248.44
Divide both sides by (1 + 6.75%)
x ≤ 16157.79
The solution means that the base price of the car cannot exceed $16157.78 for dealership A
<u>The graph of the possible base price</u>
See attachment
<h3>Dealership B</h3>The total amount of the add-on options is:
Total = $750 + $1000
Total = $1750
<u>The inequality</u>
This is represented using:
Base price * (1 + Tax) + Fees + Add-on total ≤ 20000
So, we have:
(1 + 6.75%) * x + 1524.72 + 1750 ≤ 20000
<u>Solve for x</u>
We have:
(1 + 6.75%) * x + 1524.72 + 1750 ≤ 20000
Evaluate the like terms
(1 + 6.75%) * x ≤ 16725.28
Divide both sides by (1 + 6.75%)
x ≤ 15667.71
The solution means that the base price of the car cannot exceed $15667.71 for dealership B
<u>The graph of the possible base price</u>
See attachment
<h3>Where to buy from</h3>Buy from dealership B because dealership B has a lesser base price
Read more about inequality at:
#SPJ1
9514 1404 393
Answer:
- late only: 15
- extra-late only: 24
- one type: 43
- total trucks: 105
Step-by-step explanation:
It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.
For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.
Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.
__
a) 15 trucks carried only late
b) 24 trucks carried only extra late
c) 4+15+24 = 43 trucks carried only one type
d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out
