Question

Which equation represents a line that passes through the point (9, -4) and has a slope of 3/5?

Answer 1

Answer:

Step-by-step explanation:

 

Hello:

equation is the line is : y = ax+b        a is a slope

y = (3/5)x+b

passing through the point (9;−4) :   -4 =(3/5)(9)+b

b = - 4 -27/5 = -47/5

y = (3/5)x- 47/5

Answer 2

Answer:

$(y+4)=\frac{3}{5}(x-9)$.  

Step-by-step explanation:

We have been given that a line passes through the point (9, -4) and has a slope of 3/5.

We will write the equation of given line in point-slope form of equation.

$(y-y_1)=m(x-x_1)$, where,

m = Slope of line,

$(x_1,y_1)$= Coordinates of the point on the line.

Upon substituting our given values in above formula, we will get:

$(y--4)=\frac{3}{5}(x-9)$

$(y+4)=\frac{3}{5}(x-9)$

Therefore, our required equation would be $(y+4)=\frac{3}{5}(x-9)$.