Which equation represents a line that passes through the point (9, -4) and has a slope of 3/5?
2 answers:
Answer:
.
Step-by-step explanation:
We have been given that a line passes through the point (9, -4) and has a slope of 3/5.
We will write the equation of given line in point-slope form of equation.
, where,
m = Slope of line,
= Coordinates of the point on the line.
Upon substituting our given values in above formula, we will get:
Therefore, our required equation would be .
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My "work" is to enter the equations into a graphing calculator and let it show me the answers--just as your "work" is to copy the question to Brainly.
The solutions are
(x, y) = (-0.5, 7.5)
(x, y) = (3, 25)
_____
When you equate the expressions for y, you get the quadratic
2x² -5x -3 = 0
(2x +1)(x -3) = 0
x = -1/2 or 3
y = 5(x +2) = 15/2 or 25
The solutions are
(x, y) = (-0.5, 7.5)
(x, y) = (3, 25)
_____
When you equate the expressions for y, you get the quadratic
2x² -5x -3 = 0
(2x +1)(x -3) = 0
x = -1/2 or 3
y = 5(x +2) = 15/2 or 25
<span>First thing you'll need to know is that the value for this equation is actually an approximation 'and' it is imaginary, so, one method is via brute force method.
You let f(y) equals to that equation, then, find the values for f(y) using values from y=-5 to 5, you just substitute the values in you'll get -393,-296,-225,... till when y=3 is f(y)=-9; y=4 is f(y)=48, so there is a change in </span><span>signs when 'y' went from y=3 to y=4, the answer is between 3 and 4, you can work out a little bit deeper using 3.1, 3.2... You get the point. The value is close to 3.1818...
The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so </span>
<span> where 'n' is the number you approximate, like n=0,1,2... etc. f(y) would the equation, and f'(y) is the derivative of f(y), now what you'll need to do is substitute the 'n' values into 'y' to find the approximation.</span>
You let f(y) equals to that equation, then, find the values for f(y) using values from y=-5 to 5, you just substitute the values in you'll get -393,-296,-225,... till when y=3 is f(y)=-9; y=4 is f(y)=48, so there is a change in </span><span>signs when 'y' went from y=3 to y=4, the answer is between 3 and 4, you can work out a little bit deeper using 3.1, 3.2... You get the point. The value is close to 3.1818...
The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so </span>