Answer:
<em>Diameter= 11.27 feet</em>
Step-by-step explanation:
<em>Circle = 2πr</em>
<em>or, 11.27π = 2πr</em>
<em>or, 11.27π/2π = r</em>
<em>r = 5.635 ft</em>
<em>diameter = 2r</em>
<em>= 2 x 5.635</em>
<em>= 11.27 feet</em>
answer:
<h2>F2= 5kN</h2>
step by step explanation
<em>Note the second diameter was used as 50cm and not 500cm</em>
given
F1=800N
D1=20cm
A1=πD1^2/4
=3.142*20^2/4
=314.2cm^2
D2= 50cm
A2=πD2^2/4
=3.142*50^2/4
=1963.75cm^2
The pressure applied on the smaller relative to the bigger end is expressed as
F1/A1=F2/A2
substitute we have
800/314.2=F2/1963.75
cross multiply we have
F2=800*1963.75/314.2
F2=1571000/314.2
F2=5000N
F2=5kN
The larger Force is 5kN
Answer:
![\sqrt[4]{x^5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E5%7D)
Step-by-step explanation:
A fraction exponent converts into a radical. The denominator is the index of the radical (farthest left number) and the numerator is the exponent of the base inside (the farthest right number). The base of the fraction exponent is the base number in green. To write this expression, simply the exponents into one exponent and one base.
Now convert to the radical.
![x^{\frac{5}{4}} = \sqrt[4]{x^5}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B5%7D%7B4%7D%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%5E5%7D)
Answer:
False
Step-by-step explanation:
Rewrite equation:
f(x)=1+x
Substitute X for 1:
f(1)=1+1
Combine like terms:
f(1)=2
the equation equals 2 not 0 so it is false
The answer is 3.2. you have to find the mean subtract then find the mean again
