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Vadim26 [7]
2 years ago
9

Can someone answer this question for me pls n thanks

Mathematics
1 answer:
allsm [11]2 years ago
8 0

Answer:

Mean: 29.5;    Median: 26;    Modes: 25, 26

Step-by-step explanation:

Add 10+12+25+25+26+26+30+31+33+34+47+55 = 354

Then divide it by 12      354/12 = 29.5

Mode are numbers that appear most often which in this case are 2 numbers, 25 and 26.

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dimaraw [331]
Choice J both prices are per a unit
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3 years ago
905-425
aliya0001 [1]
905 = 9 hundreds + 0 tens + 5 ones
or 8 hundreds, 10 tens, 5 ones

425 = 4 hundreds, 2 tens, 5 ones

8 hundreds, 10 tens, 5 ones
4 hundreds, 2 tens, 5 ones
---------------------------------------subtract
4 hundreds, 8 tens, 0 ones = 480......(905 - 425 = 480)
8 0
3 years ago
A proportional relationship betweeof potatoes (x) and the price in dollars (y) is graphed, and the ordered pair (4, 3) is on the
CaHeK987 [17]
4/3 = 1/x.....4 lbs potatoes to $3 = 1 lb of potatoes to $x
cross multiply
(4)(x) = (3)(1)
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3 years ago
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melomori [17]

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5 0
3 years ago
What are the intercepts of 2x + 3y – 6z = 30?
ycow [4]

Intercept of equation 2x + 3y - 6z = 30 is (15, 0, 0) , (0, 10, 0) and (0, 0, -5)

<h3><u>Solution:</u></h3>

Given equation is:

2x + 3y - 6z = 30

We have to find the intercepts

Intercept are the point where equations cut the x- axis, y- axis and z- axis.

<em><u>Thus, at x- axis :</u></em>

y and z both are zero

So substitute y = 0 and z = 0 in given equation

2x + 3(0) - 6(0) = 30

2x = 30

x = 15

<h3>Thus the intercept is (15, 0, 0)</h3>

<em><u>Thus at y - axis:</u></em>

x and z both are zero

So substitute x = 0 and z = 0 in given equation

2(0) + 3y -6(0) = 30

0 + 3y + 0 = 30

3y = 30

y = 10

<h3>Thus the intercept is (0, 10, 0)</h3>

<em><u>Thus at z - axis:</u></em>

x and y are both zero

So substitute x = 0 and y = 0 in given equation

2(0) + 3(0) - 6z = 30

-6z = 30

z = -5

<h3>Thus the intercept is (0, 0, -5)</h3>

Thus, intercept of equation 2x + 3y - 6z = 30 is (15,0,0) ,(0,10,0) and (0,0,-5)

6 0
3 years ago
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